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kaheart [24]
2 years ago
10

Select the correct answer from each drop-down menu.

Mathematics
1 answer:
ella [17]2 years ago
5 0

Answer:

A non-equilateral rhombus.

Step-by-step explanation:

We can solve this graphically.

We start with square:

ABCD

with:

A = (11, - 7)

B = (9, - 4)

C = (11, - 1)

D = (13, - 4)

Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:

AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13

BC =  √( (11 - 9)^2 + (-1 -(-4))^2) = √13

CD =  √( (11 - 13)^2 + (-1 -(-4))^2)  = √13

DA =  √( (11 - 13)^2 + (-7 -(-4))^2) = √13

And we change C by C' = (11, 1)

In the image you can see the 5 points and the figure that they make:

The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.

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3 years ago
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In Mr. Elliot's garden, 1 8 of the flowers are red, 1 4 of them are purple, and 1 4 of the remaining flowers are pink. If there
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Answer:

20

Step-by-step explanation:

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WARNING : NON SENSE ANSWER REPORT TO MODERATOR ​
Rzqust [24]

Answer:

\frac{180}{147}

Step-by-step explanation:

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=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}

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=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

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=> \frac{9}{7}

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=> \frac{180}{147}

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