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Luden [163]
3 years ago
6

What is the empirical formula of a compound that is composed of 60.94% carbon 15.36% hydrogen and 23.70% nitrogen

Chemistry
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

C₃H₉N

Explanation:

The empirical formula of a compound is the fundamental and basic possible formula that shows the mole ratio of the atoms of each element in a molecule of the compound.

mole ratio of carbon = 60.94/12 = 5.078

mole ratio of hydrogen = 15.36/1  = 15.36

mole ratio of nitrogen = 23.70/14 = 1.693

Now; we will divide by the smallest value

So; carbon = 5.078/1.693 = 2.99 ≅ 3.0

hydrogen = 15.36/1.693 = 9.07 ≅ 9.0

nitrogen = 1.693/1.693 = 1 ≅ 1

Thus,  the empirical formula is = C₃H₉N

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ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a
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Expression for rate law for first order kinetics is given by:

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