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3 years ago

Solve fasttt C7H17+O2=CO2+H2O Balancing Equations

Chemistry

1 answer:

sertanlavr [38]3 years ago

5 0

Answer:

The answer to your question is

4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O

Explanation:

Write the equation

C₇H₁₇ + O₂ ⇒ CO₂ + H₂O

Process

1.- Check if the equation is balanced

Reactants Element Products

7 C 1

17 H 2

2 O 3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂ and a coefficient of 17/2 to H₂O

C₇H₁₇ + O₂ ⇒ 7CO₂ + $\frac{17}{2}$ H₂O

Reactants Element Products

7 C 7

17 H 17

2 O 51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O

Reactants Element Products

28 C 28

68 H 68

90 O 90

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formic acid buffer containing 0.50 M HCOOH and 0.50 M HCOONa has a pH of 3.77. What will the pH be after 0.010 mol of NaOH has b

HACTEHA [7]

Answer:

pH = 3.95

Explanation:

It is possible to calculate the pH of a buffer using H-H equation.

pH = pka + log₁₀ [HCOONa] / [HCOOH]

If concentration of [HCOONa] = [HCOOH] = 0.50M and pH = 3.77:

3.77 = pka + log₁₀ [0.50] / [0.50]

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Knowing pKa, the NaOH reacts with HCOOH, thus:

HCOOH + NaOH → HCOONa + H₂O

That means the NaOH you add reacts with HCOOH producing more HCOONa.

Initial moles of 100.0mL = 0.1000L:

[HCOOH] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOOH

[HCOONa] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOONa

After the reaction, moles of each species is:

0.0500moles HCOOH - 0.010 moles NaOH (Moles added of NaOH) = 0.0400 moles HCOOH

0.0500moles HCOONa + 0.010 moles NaOH (Moles added of NaOH) = 0.0600 moles HCOONa

With these moles of the buffer, you can calculate pH:

pH = 3.77 + log₁₀ [0.0600] / [0.0400]

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3 years ago

A solution of hydrochloric acid (HCl, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was

kati45 [8]

Answer:

0.1410 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This include:

Volume of acid, HCl (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Concentration of base, NaOH (Cb) = 0.1020 M

Concentration of acid, HCl (Ca) =?

CaVa / CbVb = nA/nB

Ca × 25 / 0.1020 × 34.55 = 1/1

Ca × 25 / 3.5241 = 1/1

Cross multiply

Ca × 25 = 3.5241 × 1

Ca × 25 = 3.5241

Divide both side by 25

Ca = 3.5241 / 25

Ca = 0.1410 M

Therefore, the concentration of the acid, HCl is 0.1410 M

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Explanation:

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