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snow_tiger [21]
3 years ago
6

if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be adde

d to reach the equivalence point
Chemistry
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

14.91 mL

Explanation:

<em>Assuming the weak acid is monoprotic</em>, we can solve this problem using the equation:

  • C₁V₁=C₂V₂

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We <u>input the data</u>:

  • 25.00 mL * 0.1084 M = 0.1817 M * V₂

And solve for V₂:

  • V₂ = 14.91 mL
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5 0
3 years ago
Read 2 more answers
Pls help me
olga2289 [7]
Answer is: <span>b.20.0 L </span><span>liters of ammonia are needed to react completely.
</span>V(NO) = 30 L.
n(NO) = V(NO) ÷ Vm.
n(NO) = 30 L ÷ 22,4 L/mol.
n(NO) = 1,34 mol.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4 (3 : 2).
n(NH₃) = 4 · 1,34 mol ÷ 6.
n(NH₃) = 0,892 mol.
V(NH₃) = 0,892 mol · 22,4 L/mol.
V(NH₃) = 20 L.
3 0
3 years ago
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