Answer:
10.1g of H₂ are produced
Explanation:
To solve this question we need, first, to convert the mass of each reactant to moles and, using the chemical reaction, find limiting reactant. With limiting reactant we can find the moles of H2 and its mass:
<em>Moles Zn -Molar mass: 65.38g/mol-:</em>
307g * (1mol / 65.38g) = 4.696 moles
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
381g HCl * (1mol / 36.46g) = 10.45 moles
For a complete reaction of 10.45 moles of HCl are required:
10.45 moles HCl * (1mol Zn / 2mol HCl) = 5.22 moles Zn
As there are 4.696 moles of Zn, <em>Zn is the limiting reactant</em>
<em />
The moles of H₂ produced = Moles of Zn added = 4.696 moles. The mass is-Molar mass H₂ = 2.16g/mol-:
4.696 moles * (2.16g / mol) =
<h3>10.1g of H₂ are produced</h3>
Answer:
The answer to your question is 178.6 g
Explanation:
Data
ΔT = 1.8 °C
mass = 17.5 g
mass of water = 100 g
Kc = 1.86
Process
1.- Calculate the molality using the following formula
ΔTc = mKc
solve for m
m = ΔTc/Kc
substitution
m = 1.8/1.86
result
m = 0.968
2.- Calculate the number of moles
m = # of moles/kg of solvent
kg of solvent = 0.1 kg
# of moles = m x kg of solvent
# of moles = 0.968 x 0.1
# of moles = 0.0968
3.- Calculate the molar mass
x g molar mass --------------------- 1 mol
17.5 g --------------------- 0.0968 moles
x = (1 x 17.5)/0.0968
x = 178.6 g
What context are you asking it in?
The answer could be the electromagnetic interaction if you're talking about the 4 fundamental interactions, or ionic interaction, or electrostatic interaction.
