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Mrac [35]
3 years ago
15

this environment has lots of trees high tenpatures and high mumidity all year long which environment is this describing Grasslan

d, Rainforest, Swamp, Wetland​
Chemistry
1 answer:
Genrish500 [490]3 years ago
7 0

I believe the answer is Rainforest.

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Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15

Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63

Your answer will be about 63%. 

Hope this helped you out! :-)
5 0
3 years ago
Please can you help me from 1 to 6
jeyben [28]

Answer:

um

Explanation:

help you? you mean do it for you? nah man you can just use the calculator ;)

4 0
3 years ago
What is the PRECAUTION for an Irritant?
forsale [732]
Prevent the release of toxic vapored, dusts, mists, or gases into the workplace air
7 0
3 years ago
A sample of Cd(OH)2 is added to pure water and allowed to come to equilibrium at 25ºC. The concentration of Cd +2 = 1.7 x 10 -5M
Archy [21]

Answer:

Ksp=2.0x10^{-14}

Explanation:

Hello there!

In this case, given the solubilization of cadmium (II) hydroxide:

Cd(OH)_2(s)\rightleftharpoons Cd^{2+}(aq)+2OH^-(aq)

The solubility product can be set up as follows:

Ksp=[Cd^{2+}][OH^-]^2

Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

Ksp=(1.7x10^{-5})(3.4x10^{-5})^2\\\\Ksp=2.0x10^{-14}

Regards!

3 0
3 years ago
Please help on this question
natulia [17]
Send a more clearer picture...
But I will tell u the system of the Hadley cells---
METEOROLOGY
a large-scale atmospheric convection cell in which air rises at the equator and sinks at medium latitudes, typically about 30° north or south.
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3 years ago
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