Answer: There are 4 people who only go to the game on Saturday.
Step-by-step explanation:
Let the number of people go on Saturday be n(A).
Let the number of people go on Sunday be n(B).
Since we have given that
n(A) = 8
n(B) = 12
n(A∪B) = 16
According to rules, we get that

So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4
Hence, there are 4 people who only go to the game on Saturday.
Answer:
Your teacher is right, there is not enough info
Step-by-step explanation:
<h3>Question 1</h3>
We can see that RS is divided by half
The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS
So P is not on the perpendicular bisector of RS
<h3>Question 2</h3>
We can see that PD⊥DE and PF⊥FE
There is no indication that PD = PF or ∠DEP ≅ FEP
So PE is not the angle bisector of ∠DEF
Answer:
r=3
Step-by-step explanation:
if n=10
r=n-7
r=(10)-7
r=3
Answer:
r=9/2 or 4.5
Step-by-step explanation:
First of all our goal is to get R by itself
by cross multiplying we get,
(r+3)*3=5r
by distributive property we get
3r+9=5r
substracting 3r from both sides we get
9=2r
by dividing by 2 in both sides we get
r=9/2 or 4.5
Add all the minutes together, then divide by the number of students:
21+35+77+48+24+29+37+98+30+7 = 406 total minutes
10 students.
Average = 406 / 10 = 40.6 minutes per week.
The answer is A.