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WINSTONCH [101]
3 years ago
9

Somebody can give me a redeem code pls​

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

Lol for what

Step-by-step explanation:

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The circle below is centered at the point (-3/4) and has a radius of length 3 what is its equation??
Agata [3.3K]
{x-(-3/4)}^2=3^2
(x+3/4)^2=9
{(4x+3)/4}^2=9
(4x+3)^2/16=9
(4x+3)^2=9*16
16x^2+2*4x*3+3^2=144
16x^2+24x+9=144
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3 years ago
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Liula [17]

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c and d

Step-by-step explanation:

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3 years ago
126 point every 3 games 210 point every 3 games
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3 years ago
A tub of water drains at 3 gallons per minute. y-12=-3(x-1)
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8 0
3 years ago
The coordinates of three of the vertices of parallelogram ABCD are A(1, 0), B(2, 3), C(3, 2). What are coordinates of the fourth
nalin [4]

Answer:

 A) The coordinates of the fourth vertex are:

1) x-coordinate:

x=2

2) y-coordinate:

y=-1

B) The point of intersection of the diagonals is:  (2,1)

Step-by-step explanation:

We need to remember that the diagonals of a parallelogram intersect each other at a half-way point and the midpoint of each diagonal is the same.

The midpoint formula is:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Since:

M_{AC}=M_{BD}

We can find the coordinates of the fourth vertex D(x,y) through these procedure:

1) x-coordinate:

\frac{1+3}{2}=\frac{2+x}{2}\\\\2(2)=x\\\\4-2=x\\\\x=2

2) y-coordinate:

\frac{0+2}{2}=\frac{3+y}{2}\\\\1(2)-3=y\\\\y=-1

Therefore,  fourth vertex is D(2,-1)

Since the point of intersection of the diagonals is the midpoint of a diagonal (Remember that  M_{AC}=M_{BD}), this is:

M_{AC}=M_{BD}=(\frac{1+3}{2},\frac{0+2}{2})\\\\M_{AC}=M_{BD}=(2,1)

Therefore, the point of intersection of the diagonals is (2,1)

7 0
3 years ago
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