Answer:
Step-by-step explanation:
ah, probability, so the std. deviation is 2 MPH, so that means to get from the mean.. or average speed of 94, he'll have to vary by 3 std. deviations or 6 MPH to hit 100
99.7% of throws fall into that area of with in 3 std. deviations so that means
0.3% fall outside also , 1/2 of those will 3 std. deviations slow while the other half is fast
so
0.15% will be 100 or faster.... not many
<h3>Answer:</h3>
(5, -2, -3)
<h3>Explanation:</h3>
We assume your equations are ...
- x +3y -z = 2
- 4x +2y +5z = 1
- 3x +0y +z = 12
These have solution (x, y, z) = (5, -2, -3).
_____
<em>How we know</em>
Trying the choices in the last equation eliminates the first and last. Trying the second choice in the first equation eliminates it, leaving the 3rd choice as the answer you're looking for.
We also know because we can ask a graphing calculator to solve the matrix equation (or row-reduce the augmented matrix).
<em>Comment on this problem</em>
The hardest part of this problem is figuring your intent. The equations are not well-separated, so we have a hard time telling what is a constant and what is a coefficient. It took a couple of guesses to sort it out. A little editing before posting would be helpful.
Answer:
C
Step-by-step explanation:
Given
(3x + 7)(2x - 6)
Each term in the second factor is multiplied by each term in the first factor, that is
3x(2x - 6) + 7(2x - 6) ← distribute both parenthesis
= 6x² - 18x + 14x - 42 ← collect like terms
= 6x² - 4x - 42 → C
Answer: y=15/x
For this problem you need to use trial and error.
For the first equation, 15-14 does equal 1, but 5-14 doesn’t equal 3. For the second equation, 15x15 doesn’t equal 1. For the third equation, 15+2 doesn’t equal 1. For the last equation, 15/15 is 1, 15/5 is 3, and so on. So, the last equation shows the relationship in the table.
:)
Answer:
The arc length of the partial circle is 
Step-by-step explanation:
we know that
The circumference of a circle is equal to

In this problem we have a 3/4 of a circle
so
the circumference is equal to


we have

substitute

