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3 years ago

15

What is the factorization of the trinomial below? 4x2 + 20x - 24

1 answer:

Ivenika [448]3 years ago

6 0

Hey there!

$4x^{2} +20x -24$
We can first factor out the 4 (bring it outside the parenthesis)

$4( x^{2} +5x - 6)$
Now have a closer look between the parenthesis, because this expression can be factored as well. We're looking for two different numbers with a product of -6 and a sum of 5. Hence, we find the numbers 6 and -1

$4(x-1)(x+6)$
~ Hope this helps you!

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El taller de baile tiene tres veces la cantidad de inscritos que el taller de arte el taller de arte tiene 98 escritos menos que

Eduardwww [97]

Answer:

The number of registrants in art workshop is 49.

Step-by-step explanation:

The dance workshop has three times the number of registrants than the art workshop the art workshop has 98 less writings than the dance workshop how many registrations the art workshop has

Let the registrants in the art workshop is p.

The registrants in the dance work shop is 3 p.

According to question,

p = 3p - 98

2 p = 98

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So, the number of registrants in art workshop is 49.

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3 years ago

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Damm [24]

Answer:

$\sqrt[7]{x^{4}}$

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$(\sqrt[7]{x})^{4}$

Step-by-step explanation:

we have

$x^{\frac{4}{7}}$

Remember the properties

$\sqrt[n]{a^{m}}=a^{\frac{m}{n}}$

$(a^m)^{n}=a^{m*n}$

so

<u><em>Verify each case</em></u>

Part 1) we have

$\sqrt[4]{x^{7}}$

we know that

$\sqrt[4]{x^{7}}=x^{\frac{7}{4}}$

Compare with the given expression

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Part 2) we have

$\sqrt[7]{x^{4}}$

we know that

$\sqrt[7]{x^{4}}=x^{\frac{4}{7}}$

Compare with the given expression

$x^{\frac{4}{7}} = x^{\frac{4}{7}}$

therefore

Is equivalent to the given expression

Part 3) we have

$(x^{\frac{1}{7}})^{4}$

we know that

$(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}$

Compare with the given expression

$x^{\frac{4}{7}} = x^{\frac{4}{7}}$

therefore

Is equivalent to the given expression

Part 4) we have

$(x^{\frac{1}{4}})^{7}$

we know that

$(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}$

Compare with the given expression

$x^{\frac{7}{4}} \neq x^{\frac{4}{7}}$

Part 5) we have

$(\sqrt[4]{x})^{7}$

we know that

$(\sqrt[4]{x})^{7}=(x^{\frac{1}{4}})^{7}=x^{\frac{7}{4}}$

Compare with the given expression

$x^{\frac{7}{4}} \neq x^{\frac{4}{7}}$

Part 6) we have

$(\sqrt[7]{x})^{4}$

we know that

$(\sqrt[7]{x})^{4}=(x^{\frac{1}{7}})^{4}=x^{\frac{4}{7}}$

Compare with the given expression

$x^{\frac{4}{7}} = x^{\frac{4}{7}}$

therefore

Is equivalent to the given expression

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