In the reaction 2K + Cl2 → 2KCI, the species
1 answer:
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<h3>Solution:</h3>
x = 8
<h3>Answer: (2, 2)</h3>
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Explanation:
The phrasing "translated along <4,6>" is another way of saying "shift 4 to the right, shift 6 up"
In general, "translated along <m,n>" is the same as writing . If m is positive, then we shift m units to the right. If m is negative, then we shift to the left. The same story happens with the n, but we focus on the y coordinate.
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With all that in mind, starting at F(-5,-9) and translating along <4,6> has us arrive at (-1, -3). Add 4 to the x coordinate and add 6 to the y coordinate.
We can say
Showing that (-5,-9) moves to (-1,-3)
This is after the first translation, but there's a second translation.
We'll apply the same idea, but different numbers this time
So (-1,-3) moves to (2,2)
Overall we have
- (-5,-9) move to (-1,-3) after the first translation
- (-1,-3) move to (2,2) after the second translation
Therefore, the original point ends up at (2,2) which is the final answer
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Extra info:
A nice shortcut is that the vectors <4,6> and <3,5> can be added to get <4+3,6+5> = <7,11>. So overall, we're shifting 7 units to the right and 11 units up when we combine the two translation vectors.
The option that is true with regard to the following functions is Option B. "The domain g(x) and h(x) include all real number while the domain of i(x) and h(x) are restricted"
<h3>What is the explanation for the above?</h3>- Lets examine f(x) = 3x + 14
Note that this function is indicative of a straight-line. See the attached graph for function 1. Note that it doesn't have any end points. That is, it is Asymptote.
- Let us examine h(x) = 3ˣ + 1
This represents an exponential graph. Just like the function above it doesn't have any end point. It however has an asymptote:
y = 0
- Let us look at F'(x) = Log₃ (x = 1).
This is indicative of logarithm graph. It doesn't have any end but has an asymptote x == 0
- Let us take a look at g(x) = X⁴ + 3x² - 14
Notice that in the mid point there is an end point given as (0, -14). Thus, it is correct to state that the function in Option B is the only one that exhibits end behavior and as such is restricted.
Learn more about functions:
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