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3 years ago

N is an integer write the values of n such that

Mathematics

1 answer:

sineoko [7]3 years ago

3 0

Answer:

what did not understand (im a bot)

Step-by-step explanation:

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= 21229<br> = 72112<br> = 18284<br> ⚫️ = ?

lidiya [134]

do you mean by this

6 0

3 years ago

Please help me with these 2 questions.

Bumek [7]

Answer:

For number one the 3.75 oz container for $9.75 would be the better deal

For number two the answer is 6 1/4

3 0

3 years ago

If f:R→R is continuous at a point c∈ R and g:R→R is continuous at f(c)∈R, then the composition g(f(x)) :R→R is continuous at c.

natima [27]

Answer:

The assertion that g(f(x)) is continuous at c is true.

Step-by-step explanation:

$let\\a=\lim_{x\rightarrow c}f(x)$

$\because f(x)$ is continuous at c

$\\\\Similarly\\\\b=\lim_{x\rightarrow f(c)}g(x)$

$\because g(x)$ is continuous at $\ x=f(c)$

$\lim_{x\rightarrow c }g(f(x))=g(f(c))\\\\=g(a)$ which is defined as per given data thus g(f(x)) is continuous at x=c

5 0

3 years ago

Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified, exact value in terms o

Digiron [165]

Check the picture below.

$\stackrel{\textit{\Large Areas}}{\stackrel{triangle}{\cfrac{1}{2}(6)(6)}~~ + ~~\stackrel{semi-circle}{\cfrac{1}{2}\pi (3)^2}}\implies \boxed{18+4.5\pi} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{pythagorean~theorem}{CA^2 = AB^2 + BC^2\implies} CA=\sqrt{AB^2 + BC^2} \\\\\\ CA=\sqrt{6^2+6^2}\implies CA=\sqrt{6^2(1+1)}\implies CA=6\sqrt{2} \\\\\\ \stackrel{\textit{\Large Perimeters}}{\stackrel{triangle}{(6+6\sqrt{2})}~~ + ~~\stackrel{semi-circle}{\cfrac{1}{2}2\pi (3)}}\implies \boxed{6+6\sqrt{2}+3\pi}$

notice that for the perimeter we didn't include the segment BC, because the perimeter of a figure is simply the outer borders.

7 0

3 years ago

In two or more complete sentences, explain how to solve the cube root equation, ^3√x+1 -2=0

IrinaVladis [17]

Explanation:

The first step is to figure out what the equation is. When unconventional math symbols are used, and when there are no grouping symbols identifying operands, that can be the most difficult step. Here, we think the equation is supposed to be ...

$\sqrt[3]{x+1}-2=0$

It usually works well in radical equations to isolate the radical. Here that would mean adding 2 to both sides of the equation, to undo the subtraction of 2.

$\sqrt[3]{x+1}=2$

Now, it is convenient to raise both sides of the equation to the 3rd power.

$x+1=2^3=8$

Finally, we can isolate the variable by undoing the addition of 1. We accomplish that by adding -1 to both sides of the equation.

$x=7$

The equation is solved. The solution is x = 7.

5 0

3 years ago