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KiRa [710]
3 years ago
6

Write the equation of the line that goes through the points (-3, -2) and (4, 5).

Mathematics
1 answer:
sattari [20]3 years ago
6 0

Find the slope m.

Use the point-slope formula.

Solve for y.

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Which is equivalent to 4y-2x=16
ad-work [718]
X-intercept. y-intercept
4*0-2x=16. 4y-2*0=16
-2x+0=16. 4y-0=16
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4 0
3 years ago
Simply each expression
stealth61 [152]
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31. (x^2)^3 = x^(2 * 3) = x^6
32. (a^7)^5 = a^(7 * 5) = a^35
33. (y^13)^4 = y^(13 * 4) = y^52
34. (w^-21)^-15 = w^(-21*-15) = w^315
35. (5^2)^3 = 5^(2 * 3) = 5^6
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38. (4y^3)^2 = 4^2 y^(3 * 2) = 16y^6
39. (8c^5)^2 = 8^2 c^(5 * 2) = 64c^10
40. (-3h^9)^2 = -3^2 h^(9 * 2) = 9h^18
41. (y^4d^6)^3 = y^(4 * 3)d^(6 * 3) = y^12d^18
42. (-15h^9k^7)^3 = -15^3h^(9*3)k^(7*3) = -3375h^27k^21
43. (k^9)^5(k^3)^2 = k(9 * 5)k^(3 * 2) = (k^45)(k^6) = k^51
44. (3y^6)^2 (x^5y^2z) = 3^2y^(6*2)(x^5y^2z) = 9y^12(x^5y^2z) =   
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45. (4h^3)^2 (-2g^3h)^3 = 4^2h^(3*2) (-2^3g^(3*3)h^3) = 16h^6(-8g^9h^3)
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46. (14a^4b^6)^2 (a^6c^3)^2 = 14^2a^(4*2)b^(6*2) (a^(6*2)c^(3*2) =
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3 0
3 years ago
Read 2 more answers
SOLVE FOR X??? <br><br><img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%20%2B2%20%3D%5Cfrac%7Bx%7D%7B4%7D%2B3" id="TexFor
natima [27]

Answer:

\boxed{ \bold{ \boxed{ \sf{1. \:  \:  \:  \:  \: x = 12}}}}

\boxed{ \bold{ \boxed{ \sf{2. \:  \:  \:  \:  \: x = 3}}}}

Step-by-step explanation:

\sf{1. \:  \:  \:  \:  \frac{x}{3}  + 2 =  \frac{x}{4}  + 3}

Move x / 4 to left hand side and change its sign

Similarly, move 2 to right hand side and change it's sign

\longrightarrow{ \sf{ \frac{x}{3}  -  \frac{x}{4}  = 3 - 2}}

Take the L.C.M of 3 and 4

L.C.M of 3 and 4 = 12

\longrightarrow{ \sf{ \frac{x \times 4 - x \times 3}{12}  = 3 - 2}}

\longrightarrow{ \sf{ \frac{4x - 3x}{12}  = 3 - 2}}

\longrightarrow{ \sf{ \frac{x}{12}  = 3 - 2}}

Subtract 2 from 3

\longrightarrow{ \sf{ \frac{x}{12}  = 1}}

Do cross multiplication

\longrightarrow{ \sf{x  = 1 \times 12}}

\longrightarrow { \sf{x = 12}}

--------------------------------------------------------------------

\sf{2. \:  \:  \:  \: 3(4 + 2x) = 33 - x }

Distribute 3 through the parentheses

\longrightarrow{ \sf{12 + 6x = 33 - x}}

Move x to left hand side and change it's sign

Similarly, move 12 to right hand side and change it's sign

\longrightarrow{ \sf{6x +  x = 33 - 12}}

Collect like terms

\longrightarrow{ \sf{7x = 33 - 12}}

Subtract 12 from 33

\longrightarrow{ \sf{7x = 21}}

Divide both sides by 7

\longrightarrow{ \sf{ \frac{7x}{7}  =  \frac{21}{7} }}

Calculate

\longrightarrow{ \sf{x = 3}}

Hope I helped!

Best regards! :D

4 0
3 years ago
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