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trasher [3.6K]
3 years ago
11

A container in the shape of a pyramid has a rectangular base with dimensions of 5 inches by 15 inches. The height of the rectang

ular pyramid is 12 inches. Marbles fill half the volume of the container.
How many more cubic inches of marbles are needed to finish filling the container?

Enter your answer in the box.

in3
Mathematics
2 answers:
Rama09 [41]3 years ago
8 0

Answer:

150

Step-by-step explanation:

1) the full volume of the given pyramide may be calculated according to the formula:

V=1/3 *Area_of_base*height;

V=1/3 *(5*15)*12=300 (in³).

2) the half of the calculated volume is:

300/2=150 (in³)

aleksley [76]3 years ago
4 0

Answer:

150

Step-by-step explanation:

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3.636478334

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10x20 to the power of 5
bazaltina [42]
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5<img src="https://tex.z-dn.net/?f=5%5E%7B56%7D%20x%205%5E%7B22%7D%20x%205%5E%7B-96%7D" id="TexFormula1" title="5^{56} x 5^{22}
Akimi4 [234]

Answer:

\frac{ {11}^{56} }{ {5}^{18} }

Step-by-step explanation:

{55}^{56}  \times  {5}^{22}  \times  {5}^{ - 96}

=  {55}^{56}  \times  {5}^{ - 74}

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=  \frac{ {11}^{56} }{ {5}^{18} }

8 0
3 years ago
Suppose KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. Prove that A is equidistant from LM and KN.
Neporo4naja [7]

Answer:

This is proved by ASA congruent rule.

 Step-by-step explanation:

Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ

we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.

In ΔAPN and ΔAQL

∠PNA=∠ALQ    (∵alternate angles)  

AN=AL   (∵diagonals of parallelogram bisect each other)

∠PAN=∠LAQ      (∵vertically opposite angles)

∴ By ASA rule ΔAPN ≅ ΔAQL

Hence, by CPCT  i.e Corresponding parts of congruent triangles PA=AQ

Hence, A is equidistant from LM and KN.

7 0
3 years ago
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