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3 years ago

:

Mathematics

2 answers:

gladu [14]3 years ago

8 0

Answer: 25 home runs

Step-by-step explanation:

20% = 5

40% = 10

80% = 20

80% + 20% = 100%

5+10=25

valkas [14]3 years ago

7 0

Answer:

20 home runs left to hit.

Step-by-step explanation:

Ok so 100%/20% is 5. Increment 5 home runs until you get to 100%. So, 20% =5, 40% = 10, 80% = 15, and 100% = 20

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MariettaO [177]

Answer:

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Step-by-step explanation:

3 0

3 years ago

7 2 3 − ( 1 2 4 + 3 6 8 ) as a mixed number ASAP the denominator is not 6 thats all i know

Drupady [299]

Answer:

38,5

Step-by-step explanation:

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6 0

3 years ago

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wel

The correct answer is m<1

3 0

3 years ago

1. Find the maximum and minimum values of z = 2x + 3y subject to the following constraints

Likurg_2 [28]

Answer:

Minimum Values:

x = 0, y = 1, z = 3

Maximum Values:

x = 7 , y = 11 , z = 47

Step-by-step explanation:

FOR MINIMUM VALUES:

0<= x <= 7

It is clear from the above inequality that the minimum value of x must be 0.

y>= 1

This inequality shows that the minimum value of y must be 1. Using these minimum values of x and y to get the minimum value of z:

z = 2x + 3y

z = (2)(0) + (3)(1)

z = 3 (Minimum)

FOR MAXIMUM VALUES:

0<= x <= 7

It is clear from the above inequality that the maximum value of x must be 7.

x + y <= 11

To calculate maximum value of y we can use the minimum value of x in this inequality:

0 + y <= 11

y <= 11

Hence, the maximum value of y is 11.

Using these maximum values of x and y to get the maximum value of z:

z = 2x + 3y

z = (2)(7) + (3)(11)

z = 47 (Maximum)

3 0

3 years ago

The life of light bulbs is distributed normally. the variance of the lifetime is 625 and the mean lifetime of a bulb is 530 hour

goldfiish [28.3K]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>What is Normal Probability Distribution?</h3>

The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:

$z =\dfrac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.
Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu$ = 530 $\sigma^2$ = 625 $\sigma =$ 25

The probability of a bulb lasting for at most 569 hours is the p-value of Z when X = 569, hence:

$z =\dfrac{X - \mu}{\sigma}$

z = $\dfrac{564 -530}{25}$ = 1.36

Z = 1.36 has a p-value of 0.9131

0.9131 x 100 = 91.31 % probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

3 0

2 years ago