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f (1+1)= f (1)+8
f (2)= 27+8
f (2)=35
f (2+1)= f (2)+8
f (3)= 35+8
f (3)=43
Answer:
no solution
Step-by-step explanation:
p-4=-9+p
p=-5+p
0=-5
Answer: 59
Step-by-step explanation:
Given
2b³+5 and b=3 ⇒ 2b³+5=2(3)³+5
Simplify exponents
2(3)³+5
=2(3×3×3)+5
=2×27+5
Multiplication
=54+5
Addition
=59
Hope this helps!! :)
Please let me know if you have any questions
