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sveticcg [70]
3 years ago
5

Find the value of x...........

Mathematics
1 answer:
Flura [38]3 years ago
3 0

Answer:

x = 7°

Step-by-step explanation:

(8x + 6)° + 118° = 180°

8x = 56°

x = 7°

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QUESTION 6
IgorLugansk [536]

<u>Qu</u><u>estion</u><u> </u><u>6</u>

Step-by-step explanation:

the answer is f(a)=2a²+ 4a+5

Question 7

2a²+4ah+2h²+4a+4h+5

8 0
2 years ago
The voltage V of an audio speaker can be represented by V= 4 sqrt P ​, where P is the power of the speaker. An engineer wants to
Marysya12 [62]

Answer:

Voltage=76\ volts

Step-by-step explanation:

Given\ V=4\sqrt{P}\\\\where\ V\ is\ voltage\ and\ P\ is\ Power.

Here\ power\ is\ given\\\\P=361\ watts\\\\Substitute\ P\ in\ the\ given\ equation\\\\V=4\sqrt{P}\\\\V=4\sqrt{361}\\\\V=4\sqrt{19\times 19}\\\\V=4\times 19\\\\V=76\ volts

8 0
4 years ago
What is 5.316 - 1.942 (show ur work)
Fiesta28 [93]

Answer:

3.374

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4

\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}

\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}

\mathrm{The\:top\:digit\:is\:not\:bigger\:than\:the\:bottom\:one.\:\:Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}

\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Borrow\:}1\mathrm{\:from\:}5\mathrm{.\:\:The\:remainder\:is\:}4

\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&10&\:\:&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&3&1&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{\:\:}&\:\:&\:\:&\:\:&4\end{matrix}}

\mathrm{Add\:}1\mathrm{\:ten\:to\:}3:\quad \:10+3=13

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Borrow\:}1\mathrm{\:from\:}13\mathrm{.\:\:The\:remainder\:is\:}12

\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}

\mathrm{Add\:}1\mathrm{\:ten\:to\:}1:\quad \:10+1=11

\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:11-4=7

\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{7}&4\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:4-1=3

\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&12&11&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&\linethrough{13}&\linethrough{1}&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{3}&.&3&7&4\end{matrix}}

=3.374

Hence the correct answer is 3.374

7 0
2 years ago
Pool measuring 10 ft by 20 feet will have a cement walkway around it. The area covered by the pool and the cement walkway is 600
ki77a [65]

Answer:the width of the walkway is 5 feet

Step-by-step explanation:

Let x represent the width of the walkway.

The pool measures 10 ft by 20. If the walkway must have a uniform width around the entire pool, then the total length of the pool and the walkway would be 10 + x + x = 10 + 2x

The total width of the pool and the walkway would be 20 + x + x = 10 + 2x

The area covered by the pool and the cement walkway is 600 square feet. This means that

(10 + 2x)(20 + 2x) = 600

200 + 20x + 40x + 4x^2 = 600

4x^2 + 60x + 200 - 600 = 0

4x^2 + 60x - 400 = 0

Dividing through by 4, it becomes

x^2 + 15x - 100 = 0

x^2 + 20x - 5x - 100 = 0

x(x + 20) - 5(x + 20) = 0

(x - 5)(x + 20) = 0

x = 5 or x = - 20

The width cannot be negative. Therefore, the width of the walkway is 5 feet

8 0
3 years ago
Find the measure of the indicated angle to the nearest degree
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

    sin Ф = 0.9697

        Ф = 75.86°

15) sin Ф = 16/36

     sin Ф = 0.444

          Ф = 26.39°

16) sin Ф = 29/36

     sin Ф = 0.806

          Ф = 53.66°

17) cos Ф = 11/34

    cos Ф = 0.324

          Ф = 71.12°

18) sin Ф = 21/40

     sin Ф = 0.525

           Ф = 31.67°

19) cos Ф = 6/14

     cos Ф = 0.429

          Ф = 64.62°

20) cos Ф = 38/39

      cos Ф = 0.974

            Ф = 13°

3 0
3 years ago
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