A^2 - 6a/a-6 • a+3/a
a(a - 6)/(a - 6) • a+3/a
a • (a + 3)/a
a(a+3)/a
a+3.
The correct solution to this question would be B. a+3.
If I remember correctly perpendicular means right angle so I do not think it could be reversed.
For any inscribed quadrilateral, the opposite angles add to 180
(angle PMN) + (angle NOP) = 180
(8x-24) + (4x) = 180
12x-24 = 180
12x-24+24 = 180+24 ..... add 24 to both sides
12x = 204
12x/12 = 204/12 ..... divide both sides by 12
x = 17
angle NOP = 4x
angle NOP = 4*17
<h3>
angle NOP = 68 degrees</h3>
56-16=40+23=63. ×=63
63-23=40+16=56
Reverse the problem it helps!
