I need help please

The roman number of 30 is

padilas [110]

Answer:

XXX

Step-by-step explanation:

10+10+10 if that helps

6 0

3 years ago

Which represents the polynomial written in standard form?

bekas [8.4K]

Polynomial written in standard form includes polynomial in which its term of highest degree is first, its term of 2nd highest is 2nd etc.
According this definition , the polynomial written in standard form are:
4x4 – 7xy3 – + 8x2y2

8 0

3 years ago

Read 2 more answers

ASAP options: left right up down

Alenkinab [10]

Right 6 and down 5 hope this helps you out

5 0

3 years ago

In statistical inference for categorical data:___________.

a_sh-v [17]

Answer:

b. Normal data is never one of the inference assumptions.

Step-by-step explanation:

A categorical data specifies among two or more groups, which one each observation belongs to, and one or more explanatory variables that can be used to predict this membership.

So, there are two propositions in statistical inference for categorical data

1. That each data in a cell is independent of the others.

2. That samples are randomly drawn.

Thus, there is no room for normality.

6 0

3 years ago

e. A set of observations has a mean of 9.0 and standard deviation 4.0. Another set of 20 observations has a mean of 10.0. Given

melisa1 [442]

From the combined standard deviation, with the mean, and standard

deviation of the data sets, the required variance can be found.

$\underline{\mathrm{The \ variance \ of \ the \ second \ set \ is} \ 4\dfrac{5}{28}}$

Reasons:

The given data information are;

Mean of the first set of observation, $\overline x_1$ = 9.0

Standard deviation of the the first set, σ₁ = 4.0

Sample size of second observation, n₂ = 20

Mean of second sample, $\overline x_2$ = 10

Standard deviation of the combined set, σ₁₂ = 3.0

Sample size of combined set of observation, n₂ = 35

Solution:

The number of elements in the second sample, n₁ = 35 - 20 = 15

The standard deviation of the combined set is given by the formula;

${\sigma_{12}} = \mathbf{\sqrt{\dfrac{n_1 \cdot \left ( \sigma^2_{1}-d_1^2 \right ) + n_2 \cdot \left ( \sigma^2_{2}-d_2^2 \right )}{n_{1}+n_{2}}}}$

Where;

$\overline x_{12} =\mathbf{\dfrac{n_1 \cdot \overline x_1 +n_2 \cdot \overline x_2 }{n_1 + n_2}}$

Therefore;

$\overline x_{12} =\dfrac{15 \times 9.0 +20 \times10.0 }{15 + 20} = \dfrac{67}{7}$

d₁ = $\mathbf{\overline x_{12}}$ - $\mathbf{\overline x_1}$

$d_1 = \dfrac{67}{7} - 9.0 = \dfrac{4}{7}$

d₂ = $\mathbf{\overline x_{12}}$ - $\mathbf{\overline x_2}$

$d_2 = \dfrac{67}{7} - 10.0 = -\dfrac{3}{7}$

Therefore;

$3=\sqrt{\dfrac{15 \times \left ( 4.0^2-\left(\dfrac{4}{7}\right) ^2 \right ) + 20 \cdot \left ( \sigma^2_{2}-\left(-\dfrac{3}{7}\right) ^2 \right )}{15+20}}$

Solving gives;

$Variance, \ \sigma^2_2 = \mathbf{\dfrac{{117} }{28}}$

$\mathrm{The \ variance \ of \ the \ second \ set, \ \sigma_2^2} = \dfrac{{117} }{28} = 4\dfrac{5}{28}$

Learn more here:

brainly.com/question/16869429

3 0

3 years ago

I need help please ​

I need help please