We know that
if the club includes one set of identical
triplets wearing matching clothes
then
the number of different arrangements that are
possible is
10! / 3! = (10*9*8*7*6*5*4*3!)/3!
=604,800
The answer is
<span>604,800</span>
Answer: Option <span>C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.
First equation of system A multiplied by -3:
(-3)(x+6y=5)
(-3)(x)+(-3)(6)=(-3)(5)
-3x-18=-15
Sum of the second equation of system A and the first equation multiplied by -3:
(-3x-18)+(3x-7y)=(-15)+(-35)
-3x-18+3x-7y=-15-35
-25y=-50
System B
x+6y=5
-25y=-50 </span>
The product of five and FOUR is twenty.
A,C,E
you should check that the second number is more than 7 and if you multiply the first number by 2 you will get less than the second number.
Answer:
5.6 * 10^5
Step-by-step explanation:
If 5 is your number, the power of 10 has to be how many digits come after it. 5<u>60000</u>. Five digits come after, making that your power of 10.
