Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
858 i believe...
546/7
78 x 4 (compound a)
312 + original compound b (546)
Hope I helped!
Giving me brainliest is much appreciated! =)
Answer:
65
Step-by-step explanation:
All the angles in a right triangle add up to 180
plug in what we know and we get
90+25+x=180
115+x=180
x=65
1, 3, 9 and -1, -3, and -9 i guess
hope this helps
1. 22 - 3x + 7x = 4(x + 5)
22 - 3x + 7x = 4x + 20
<u> +3x +3x +3x </u>
22 + 10x = 7x + 20
<u> -7x -7x </u>
22 + 3x = 20
<u>-22 -22</u>
<u>3x</u> = -<u>2</u>
3 3
x = -2/3
2. 6(2x - 3) = 3(3 - 5)
12x - 18 = 3(-2)
12x - 18 = -6
<u> +18 +18</u>
<u>12x</u> = <u>12</u>
12 12
x = 1
3. 6x - 14 = 2(3x - 7)
6x - 14 = -3x
6x - 14 = 2(-7)
6x - 14 = -14
<u> +14 +14</u>
<u>6x</u> = <u>0</u>
6 6
x = 0
4. 6x + 3(x - 4) = 8(x - 3)
6x + 3x - 12 = 8x - 24
9x - 12 = 8x - 24
<u>-8x -8x </u>
x - 12 = -24
<u> +12 +12</u>
x = -12
