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3 years ago

I need help with this ASAPP

Mathematics

2 answers:

torisob [31]3 years ago

7 0

Answer:

Step-by-step explanation:

you can see the factors in the green section of the venn diagram. Of all the factors, 6 is the largest.

Hope this helps!

Airida [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Im not complety sure but just do it I guess :)

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A bottle contains 255 coins. 1/3 of the coins are ?1.00. 110 of the coins are 50p coins. the rest are 20p coins. work out the to

aliina [53]

Answer:

£152.

Step-by-step explanation:

We have been given that a bottle contains 255 coins. 1/3 of the coins are £1.00.

Let us find 1/3 of 255 to find the number of £1 coins.

$\£1\text{ coins}=\frac{1}{3}\times 255$

$\£1\text{ coins}=85$

This means we have £85.

We are also told that 110 of the coins are 50 p coins.

$\text{Value of 50 p coins}=\£0.50\times 110$

$\text{Value of 50 p coins}=\£55$

Let us figure out number of 20 p coins by subtracting the number of £1 coins and 50 p coins from 255.

$\text{Number of 20 p coins}=255-(85+110)$

$\text{Number of 20 p coins}=255-(195)$

$\text{Number of 20 p coins}=60$

$\text{Value of 20 p coins}=\£0.20\times 60$

$\text{Value of 20 p coins}=\£12$

Now let us find total value of the coins contained in the bottle by adding the values of £1 coins, 50 p coins and 20 p coins.

$\text{The total value of the coins}=\£85+\£55+\£12$

$\text{The total value of the coins}=\£152$

Therefore, the total value of the coins contained in the bottle is £152.

4 0

3 years ago

Read 2 more answers

6a and 6b are having a competition to see who can make the most money for Red Crescent. 6a make $2 for every $3 that 6b make. If

GaryK [48]

Answer:

Step-by-step explanation:

6a 6b

2 : 3

30 : x

30×3

=45

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N is prime given that it has 2 digits

rjkz [21]

Minimum 11, Maximum 97

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Solve g + (-11) = 19 for g?

Papessa [141]

Answer:

g = 30

Step-by-step explanation:

Plus with minus inside brackets give us minus

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Simplify the expression r^-3 s^5 t^2/r^2 st^-2

Hoochie [10]

R/s^5t^r2st-2/r^3
hope this helps

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3 years ago