Answer:
Step-by-step explanation:
On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?
Let:
RM 30 = x
RM 50 = y
x + y = 800 - - - (1)
30x + 50y = 30000 - - - (2)
From (1)
x = 800 - y
Put x = 800 - y in (2)
30(800 - y) + 50y = 30000
24000 - 30y + 50y = 30000
24000 + 20y = 30000
20y = 30000 - 24000
20y = 6000
y =
S= number of small boxes
l= number of large boxes
equation 1: s+l=120
equation 2: 15s+45l=3300
solve by elimination, multiply equation 1 by -15.
-15(s+l=120) = -15s-15l=-1800 add to equation 2.
-15s+15s-15l+45l=-1800+3300 = 30l=1500
30l=1500 , l=50
s+l=120, s+50=120 --> s=70
Answer:
Step-by-step explanation:
Let's start by decoding this :)
First lets do 60% more than 10; 16 (mental math)
Next, lets do 20% less than 16; x/16 = 80/100 (Equation)
After solving by cross multiplying & then simplifying (make sure both denominators are 100), you should get 12.8 as your final #! Hope this helped.
Answer:
If $657 is 27% off, then $657 = 100-27% or 73%.
So you want to know what's 100%. So you use a ratio. 100/73 * $657. Which equals $900.
Step-by-step explanation:
