Answer:
To save the course object instances in an array, use;
Course[] courses = new Course[7];
courses[0] = new Course("IT 145");
courses[1] = new Course("IT 200");
courses[2] = new Course("IT 201");
courses[3] = new Course("IT 270");
courses[4] = new Course("IT 315");
courses[5] = new Course("IT 328");
courses[6] = new Course("IT 330");
Explanation:
The java statement above assigns an array of size 7 with the course class constructor, then order courses are assigned to the respective indexes of the new array.
Computer hacking<span> refers to the practice of modifying or altering </span>computer<span> software and hardware to accomplish a goal that is considered to be outside of the creator's original objective.
</span>
“bot,” is a computer under the control of a hacker <span>without the knowledge of the computer user.</span>
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
= 
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
Poster because if you have that much space....well what I do is calculate it by the centimeters in square divide:)
