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Evgesh-ka [11]
3 years ago
13

The base of a triangle is g mand the height is 27m.

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

Step-by-step explanation:

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Two angles are supplementary the first angle measures 40 degrees what is the second angle
nydimaria [60]
The second angle would be 140⁰. When two angles are supplementary, they add up to 180⁰.
180⁰-40⁰=140⁰
4 0
3 years ago
Math question please show work for brainliest :)
yKpoI14uk [10]
Hello!
First of all you look at how many X's the line moves by, in this case it is -3

Then you look at how many y's the line moves by, in this case it is -2

Then you add together the number of X's moved and the number of y's moved:
-3x + -2y
( adding a negative number is the same as subtracting that number)
thus the answer is A. -3x-2y

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5 0
3 years ago
Write the ratio of the first measurement to the second measurement. Compare in millimeters.
larisa86 [58]

Answer:

8:19

Step-by-step explanation:

Ball B:  diameter in mm = 9.5 * 10 = 95 mm

Ratio of Ball A to Ball B = 40 : 95

=  8:19 answer

5 0
3 years ago
Read 2 more answers
Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ
gulaghasi [49]

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf =  {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf  = 30184 / 1241

Δf  = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41  

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

6 0
3 years ago
LAST QUESTION ON MATH TEST. HELP
Feliz [49]

Answer:

its C

Step-by-step explanation:

7 0
3 years ago
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