Can Someone Help please

For what value of a does (1/9)^a+1 =81^a+1 x 27^2-a ? -4 -2 2 6

EastWind [94]

Answer:

- 4

Step-by-step explanation:

Using the rule of exponents

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

• $a^{-m}$ ⇔ $\frac{1}{a^{m} }$

$(\frac{1}{9}) ^{a+1}$ = $9^{-(a+1)}$ = $3^{-2(a+1)}$

and right side

= $3^{4(a+1)}$ × $3^{3(2-a)}$

Hence

$3^{-2a-2}$ = $3^{4a+4}$ × $3^{6-3a}$

$3^{-2a-2}$ = $3^{a+10}$

Equating exponents on both sides gives

a + 10 = - 2a - 2 ( add 2a to both sides )

3a + 10 = - 2 (subtract 10 from both sides )

3a = - 12 ( divide both sides by 3 )

a = - 4

4 0

4 years ago

Read 2 more answers

Choose the correct symbol to form a true statement. 11 over 18 ____5 over 9

dem82 [27]

11/18 is greater than ( > ) 5/9

4 0

4 years ago

In 2015, Oklahoma experienced 907 perceptible earthquakes (far surpassing California), for an average of about 2.5 perceptible e

Rufina [12.5K]

Answer:

The probability P of a day with no perceptible earthquakes is 0.0821.

Step-by-step explanation:

We will consider that earthquakes occurring in a day is a Poisson process. The following Poisson probability distribution formula will be used in this question.

p(x,λ) = [e^-λ (λ)ˣ]/x!

where x = number of outcomes occurring

λ = mean number of occurrences

(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,

P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!

= ((0.0821)*1)/1

P(X=0) = 0.0821

The probability P of a day with no perceptible earthquakes is 0.0821.

6 0

4 years ago

Sketch a graph that has the following characteristics. (8 points: 2 points for each characteristic) a. Crosses the y-axis at (0,

dimaraw [331]

Answer:

I would appreciate if my answer is chosen as a brainliest answer

4 0

3 years ago

Read 2 more answers

Find the equation of the line through the points (0, –3) and (4, 5)

vekshin1

Answer:

y=2x-3

Step-by-step explanation:

Hi there!

We are given the points (0, –3) and (4, 5)

We want to find the equation of the line between these points

There are 3 ways to write the equation of the line, yet the most common way is slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

To write the equation of the line in this way, we need to first find the slope of the line
The slope can be found using the formula $\frac{y_2-y_1}{x_2-x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We already have 2 points, but let's label their values to avoid confusion and mistakes when calculating.

m= $\frac{y_2-y_1}{x_2-x_1}$

m= $\frac{5--3}{4-0}$

Simplify

m= $\frac{5+3}{4-0}$

m= $\frac{8}{4}$

Divide

m=2

We found the slope of the line.

Here is the equation of the line so far:

y=2x+b

Now let's find b

As stated before, b is the y intercept of the line, which is the point where the line passes through the y axis; the value of x at the y intercept is 0

One of the points we were given (0, -3) is actually the y intercept of the line!

The value of b is the value of y at the y intercept; in this case, b is equal to -3

Now substitute -3 as b in the equation.

y=2x-3

Hope this helps!

See more on this topic here: brainly.com/question/27172025

5 0

2 years ago