Answer:
a true
b false
c. false
d. true
e. false
f. true
Step-by-step explanation:
The function is y =35+8x where x is the number of items sold and y is the earnings
To determine if the point is on the graph substitute the point in and see if it is true
a (7,91)
91 = 35+ 8(7)
91 = 35+ 56
91 = 91 true
b(11, 121)
121 = 35+ 8(11)
121 = 35+ 88
121 = 123 false
c. (9, 110)
110 = 35+ 8(9)
110 = 35+ 72
110 = 107 false
d. (4,67)
67 = 35+ 8(4)
67 = 35+ 32
67 = 67 true
e. (5,72)
72 = 35+ 8(5)
72 = 35+ 40
72 = 75 false
f. (3, 59)
59 = 35+ 8(3)
59 = 35+ 24
59 = 59 true
<h3>
Answer: A. 18*sqrt(3)</h3>
=============================================
Explanation:
We'll need the tangent rule
tan(angle) = opposite/adjacent
tan(R) = TH/HR
tan(30) = TH/54
sqrt(3)/3 = TH/54 ... use the unit circle
54*sqrt(3)/3 = TH .... multiply both sides by 54
(54/3)*sqrt(3) = TH
18*sqrt(3) = TH
TH = 18*sqrt(3) which points to <u>choice A</u> as the final answer
----------------------
An alternative method:
Triangle THR is a 30-60-90 triangle.
Let x be the measure of side TH. This side is opposite the smallest angle R = 30, so we consider this the short leg.
The hypotenuse is twice as long as x, so TR = 2x. This only applies to 30-60-90 triangles.
Now use the pythagorean theorem
a^2 + b^2 = c^2
(TH)^2 + (HR)^2 = (TR)^2
(x)^2 + (54)^2 = (2x)^2
x^2 + 2916 = 4x^2
2916 = 4x^2 - x^2
3x^2 = 2916
x^2 = 2916/3
x^2 = 972
x = sqrt(972)
x = sqrt(324*3)
x = sqrt(324)*sqrt(3)
x = 18*sqrt(3) which is the length of TH.
A slightly similar idea is to use the fact that if y is the long leg and x is the short leg, then y = x*sqrt(3). Plug in y = 54 and isolate x and you should get x = 18*sqrt(3). Again, this trick only works for 30-60-90 triangles.
ANSWER
Step-by-step explanation:
<h3>EXAMPLES</h3><h3>monomial:-20y</h3><h3>binomial:-25x+70y</h3><h3>trinomial:-13x+17y+√16</h3><h3>Degree of polynomial of 15x^2 is </h3>
DEGREE =2
Answer:
113.142857 m²
Step-by-step explanation:
As per the provide information in the given question, we have :
- Radius of the circular ground = 6 m
We are asked to find the area of the ground.
Since, it is in the shape of circle, so we'll apply here the formula to find the area of the circular ground.
We know that,
>> Area of circle = πr
>> Area of the ground = 
× 6 m × 6 m
>> Area of the ground = × 36 m²
>> Area of the ground = 
m²
>> Area of the ground = 113.142857 m²
<u>Therefore</u><u>,</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ground</u><u> </u><u>is</u><u> </u><u>113.142857 m²</u><u>.</u><u> </u>
