The nucleus is made of protons and neutrons
Missing text find on internet: a<span> 90,0 mL sample of water is heated to its boiling point.
V(H</span>₂O) = 90,0 mL.
d(H₂O) = 1,00 g/mL.
m(H₂O) = 90 mL · 1,00 g/mL.
m(H₂O) = 90 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 90 g ÷ 18 g/mol.
n(H₂O) = 5 mol.
Q = n(H₂O) · ΔHvap
Q = 5 mol · 40.65 kJ/mol.
Q = 203,250 kJ.
Q - heat reqiured.
Answer:
The value is
Explanation:
From the question we are told that
The equilibrium spacing is ![r = 0.074 nm= 0.074 *10^{-9} \ m](https://tex.z-dn.net/?f=r%20%3D%200.074%20nm%3D%200.074%20%2A10%5E%7B-9%7D%20%5C%20%20m)
The mass of a hydrogen atom is ![m = 1.67 *10^{-27} \ kg](https://tex.z-dn.net/?f=m%20%3D%20%201.67%20%2A10%5E%7B-27%7D%20%5C%20%20kg)
The principal quantum number of the second energy level is ![l = 3](https://tex.z-dn.net/?f=l%20%3D%20%203)
The principal quantum number of the first energy level is ![l = 2](https://tex.z-dn.net/?f=l%20%3D%20%202)
Given that the hydrogen molecule is a symmetrical diatomic molecule, its moment of inertia is mathematically represented as
![I = \frac{m}{2} r^2](https://tex.z-dn.net/?f=I%20%3D%20%20%5Cfrac%7Bm%7D%7B2%7D%20%20r%5E2)
Generally for rotational spectrum the energy level is mathematically represented as
![E = l(l + 1) * \frac{h^2}{8 \pi ^2 I}](https://tex.z-dn.net/?f=E%20%20%3D%20l%28l%20%2B%201%29%20%2A%20%5Cfrac%7Bh%5E2%7D%7B8%20%5Cpi%20%5E2%20I%7D)
Generally the energy difference between the first energy level and the second energy level is mathematically represented as
![\Delta E = [ l_2(l_2 + I) * \frac{h^2}{8 \pi ^2 I}]- [ l_1(l_1 + I) * \frac{h^2}{8 \pi ^2 I}]](https://tex.z-dn.net/?f=%5CDelta%20E%20%20%3D%20%5B%20l_2%28l_2%20%2B%20I%29%20%2A%20%5Cfrac%7Bh%5E2%7D%7B8%20%5Cpi%20%5E2%20I%7D%5D-%20%5B%20l_1%28l_1%20%2B%20I%29%20%2A%20%5Cfrac%7Bh%5E2%7D%7B8%20%5Cpi%20%5E2%20I%7D%5D)
=> ![\Delta E = [ 3(3 + 1) * \frac{h^2}{8 \pi ^2 I}]- [ 2(2 + 1) * \frac{h^2}{8 \pi ^2 I}]](https://tex.z-dn.net/?f=%5CDelta%20E%20%20%3D%20%5B%203%283%20%2B%201%29%20%2A%20%5Cfrac%7Bh%5E2%7D%7B8%20%5Cpi%20%5E2%20I%7D%5D-%20%5B%202%282%20%2B%201%29%20%2A%20%5Cfrac%7Bh%5E2%7D%7B8%20%5Cpi%20%5E2%20I%7D%5D)
=> ![\Delta E = \frac{6h^2}{8 \pi ^2 I}](https://tex.z-dn.net/?f=%5CDelta%20E%20%20%3D%20%20%5Cfrac%7B6h%5E2%7D%7B8%20%5Cpi%20%5E2%20I%7D)
substituting for I
![\Delta E = \frac{6h^2}{8 \pi ^2 [\frac{m}{2} * r^2]}](https://tex.z-dn.net/?f=%5CDelta%20E%20%20%3D%20%20%5Cfrac%7B6h%5E2%7D%7B8%20%5Cpi%20%5E2%20%5B%5Cfrac%7Bm%7D%7B2%7D%20%2A%20r%5E2%5D%7D)
=> ![\Delta E = \frac{3h^2}{2 \pi ^2 m * r^2}](https://tex.z-dn.net/?f=%5CDelta%20E%20%20%3D%20%20%5Cfrac%7B3h%5E2%7D%7B2%20%5Cpi%20%5E2%20m%20%2A%20r%5E2%7D)
Generally this difference in energy level can also be mathematically represented as
![\Delta E = \frac{hc}{\lambda}](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D)
=>
=>
Here h is Planck's constant with value ![h = 6.62607015 * 10^{-34} J \cdot s](https://tex.z-dn.net/?f=h%20%3D%206.62607015%20%2A%2010%5E%7B-34%7D%20J%20%5Ccdot%20s)
and c is the speed of light with value ![c = 3.0*10^{8} \ m/s](https://tex.z-dn.net/?f=c%20%3D%20%203.0%2A10%5E%7B8%7D%20%5C%20%20m%2Fs)
So
=>
=>
=>
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
double replacement .... :d