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gulaghasi [49]
3 years ago
14

A compound such as CaCl, would have an overall charge of?

Chemistry
1 answer:
Rina8888 [55]3 years ago
7 0

Calcium Chloride would have a charge of +2

Hopes this helps :)

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Suppose that the mixture in problem 4 is at 15 OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for etha
EleoNora [17]

Answer:

Explanation:

Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.

Using Raoult's Law:

P_A = (P_o)_A*X_A

For water:

(P)w = P_o \times \text{mole fraction of water}

where P_o of water = 12.5 mmHg

Then, the vapor pressure of water:

(P)w = 12.5 \ mmHg \times \text{mole fraction of water}

For ethanol:

P_E = P_o \times \text {mole fraction of ethanol}

and the P_o of ethanol = 32.1 mmHg

Then, the vapor pressure of ethanol:

P_E = 32.1 \ mmHg \times \text {mole fraction of ethanol}

The total vapor pressure T_P = P_W + P_E

The total vapor pressure = (12.5 \ mmHg \times \text{mole fraction of water}) + (32.1 \ mmHg \times \text {mole fraction of ethanol})

3 0
3 years ago
A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation
AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ (P+\frac{n^2 a}{v^2} )(v-nb)=nRT

or,

⇒ P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}

       =\frac{(0.467)^2\times 3.49}{(0.245)^2}

       =73.61-13.05

       =60.56 \ atm

8 0
3 years ago
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The answer is element
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3 years ago
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Which of these radioactive waste elements would be stored at New Mexico's Waste Isolation Pilot Plant?
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C and D they're both right
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3 years ago
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Cu + 2AgNO3 mc021-1.jpg Cu(NO3)2 + 2Ag The molar mass of Cu is 63.5 g/mol. The molar mass of Ag is 107.9 g/mol. What mass, in gr
Ray Of Light [21]
31.79 g Cu / 63.5 g/mol Cu ---> 0.5
0.5 * (2/1) ---> 1
1 * 107.9 g/mol Ag

107.9 grams
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