Answer:
Explanation:
The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.
1 .Calculate the hydronium ion concentration
We can use an ICE table to organize the calculations.
HF + H₂O ⇌ H₃O⁺ + F⁻
I/mol·L⁻¹: 2.7 0 0
C/mol·L⁻¹: -x +x +x
E/mol·L⁻¹: 2.7 - x x x
2. Calculate the pH
3. Calculate [C₆H₅O⁻]
C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺
2.7 x 0.0441
Answer:
Two conversion factors:
Explanation:
You can create two possible <em>conversion factors</em>, one to convert from mL to L, and one to convert from L to mL
<u />
<u>a) From mL to L</u>
To convert mL to L you need to multiply by a conversion factor that has mL on the denominator and L in the numerator.
Your starting point is:
Then, divide both sides by 1,000mL (this will be on the denominator of the fraction);
<u>b) From L to mL</u>
Divide both sides by 1 L: