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ozzi
3 years ago
7

James works in a flower shop.He will put 36 tulips in vases for wedding.He must use the same number of tulips in each vase.How m

any tulips could be in each vase
Mathematics
1 answer:
Maru [420]3 years ago
8 0
6 because there would be the same number of tulips in each vase and same name of vases. 6 x 6 is 36
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Please help! Show all work pls. Thx!
tigry1 [53]

Answer:

the right anawer is A

44 cups

8 0
3 years ago
A bonus of £2100 is shared by 10 people who work for a company. 40 percent of the bonus is shared equally between 3 managers. Th
Alja [10]

Answer:

Salesman is not correct

Step-by-step explanation:

First we calculate the share of salesman when 60 percent of bonus is shared among 7 salesmen:

Bonus Share For 7 Salesmen = (0.6)(£ 2100)

Bonus Share For 7 Salesmen = £ 1260

Now, this is equally divided among 7 salesmen:

Bonus Share of 1 Salesmen (when 60% is shared) = S₁ = £ 1260/7

S₁ = £ 180

Now, we calculate the share each salesmen get if bonus is equally divided among 10 people:

Bonus Share of 1 Salesmen (when equally shared) = S₂ = £ 2100/10

S₂ = £ 210

S₂/S₁ = £ 210/£ 180

S₂/S₁ = 1.16

S₂ = 1.16S₁

S₂ = 116% of S₁

This means that if bonus is equally divided between all 10 people then the salesman will get 16 percent more money.

<u>Therefore, salesman is not correct</u>

6 0
3 years ago
Hello again! This is another Calculus question to be explained.
podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Functions

  • Function Notation
  • Exponential Property [Rewrite]:                                                                   \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Property [Root Rewrite]:                                                           \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the following and are trying to find the second derivative at <em>x</em> = 2:

\displaystyle f(2) = 2

\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}

When we differentiate this, we must follow the Chain Rule:                             \displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]

Use the Basic Power Rule:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big]

Simplifying it, we have:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]

We can rewrite the 2nd derivative using exponential rules:

\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}

To evaluate the 2nd derivative at <em>x</em> = 2, simply substitute in <em>x</em> = 2 and the value f(2) = 2 into it:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}

When we evaluate this using order of operations, we should obtain our answer:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0
3 years ago
Can you create a pattern with the rule n*2+1
Citrus2011 [14]
3, 5, 7, 9, 11, etc.
4 0
3 years ago
Plz i need help walk me through it, thanks​
SVETLANKA909090 [29]

Answer:

p=36^{\circ}

Step-by-step explanation:

We can prove that a tangent will always be perpendicular to the radius touching it. So, the other angle in the diagram is 90^{\circ}.

Because all the angles of a triangle sum to 180^{\circ}, we have that p+54+90=180.

We combine like terms on the left side to get p+144=180.

We subtract 144 on both sides to get p=36.

So, \boxed{p=36^{\circ}} and we're done!

6 0
3 years ago
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