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3 years ago

7

James works in a flower shop.He will put 36 tulips in vases for wedding.He must use the same number of tulips in each vase.How m

any tulips could be in each vase

1 answer:

Maru [420]3 years ago

8 0

6 because there would be the same number of tulips in each vase and same name of vases. 6 x 6 is 36

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Please help! Show all work pls. Thx!

tigry1 [53]

Answer:

the right anawer is A

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3 years ago

A bonus of £2100 is shared by 10 people who work for a company. 40 percent of the bonus is shared equally between 3 managers. Th

Alja [10]

Answer:

Salesman is not correct

Step-by-step explanation:

First we calculate the share of salesman when 60 percent of bonus is shared among 7 salesmen:

Bonus Share For 7 Salesmen = (0.6)(£ 2100)

Bonus Share For 7 Salesmen = £ 1260

Now, this is equally divided among 7 salesmen:

Bonus Share of 1 Salesmen (when 60% is shared) = S₁ = £ 1260/7

S₁ = £ 180

Now, we calculate the share each salesmen get if bonus is equally divided among 10 people:

Bonus Share of 1 Salesmen (when equally shared) = S₂ = £ 2100/10

S₂ = £ 210

S₂/S₁ = £ 210/£ 180

S₂/S₁ = 1.16

S₂ = 1.16S₁

S₂ = 116% of S₁

This means that if bonus is equally divided between all 10 people then the salesman will get 16 percent more money.

<u>Therefore, salesman is not correct</u>

6 0

3 years ago

Hello again! This is another Calculus question to be explained.

podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Functions

Function Notation

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

We are given the following and are trying to find the second derivative at <em>x</em> = 2:

$\displaystyle f(2) = 2$

$\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}$

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

$\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}$

When we differentiate this, we must follow the Chain Rule: $\displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]$

Use the Basic Power Rule:

$\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')$

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

$\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big]$

Simplifying it, we have:

$\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]$

We can rewrite the 2nd derivative using exponential rules:

$\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}$

To evaluate the 2nd derivative at <em>x</em> = 2, simply substitute in <em>x</em> = 2 and the value f(2) = 2 into it:

$\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}$

When we evaluate this using order of operations, we should obtain our answer:

$\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

3 years ago

Can you create a pattern with the rule n*2+1

Citrus2011 [14]

3, 5, 7, 9, 11, etc.

4 0

3 years ago

Plz i need help walk me through it, thanks

SVETLANKA909090 [29]

Answer:

$p=36^{\circ}$

Step-by-step explanation:

We can prove that a tangent will always be perpendicular to the radius touching it. So, the other angle in the diagram is $90^{\circ}$ .

Because all the angles of a triangle sum to $180^{\circ}$ , we have that $p+54+90=180$ .

We combine like terms on the left side to get $p+144=180$ .

We subtract $144$ on both sides to get $p=36$ .

So, $\boxed{p=36^{\circ}}$ and we're done!

6 0

3 years ago