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Mila [183]
3 years ago
9

Which of these fractions are greater than 11/20 A - 3/4 B - 3/10 C - 4/5 D - 1/2

Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

3/4 and 4/5

Step-by-step explanation:

Convert into decimals:

11/20 = 0.55

3/4 = 0.75

3/10 = 0.3

4/5 = 0.8

1/2 = 0.5

075 and 0.8 are greater than 0.55, so 3/4 & 4/5

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187.69 because 3003.04 divided by 16 is 187.69
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Find the quotient. (i'll give 30 points)
marissa [1.9K]
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Hope that helps!
7 0
3 years ago
The countries of Europe report that 46% of the labor force is female. The United Nations wonders if the percentage of females in
Anestetic [448]

Answer:

a) Point estimate p=0.43.

b) The 95% confidence interval for the population proportion of female workers in US is (0.388, 0.473).

c) This confidence interval tells us that, with 95% confidence, the true proportion of females in the U.S. labor force is within 0.388 and 0.473.

d) We can conclude that females do not make up a majority of the US labor force, because we can claim, with 95% confidence, that the true proportion of female workers is under 0.473, which is below 0.5 (or 50%).

Step-by-step explanation:

a) A point estimate can be calculated using the sample results and dividing the amount of female workers in the sample by the sample size:

p=X/n=226/525=0.43

b) We have to calculate a 95% confidence interval for the proportion.

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.43*0.57}{525}}\\\\\\ \sigma_p=\sqrt{0.000467}=0.022

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.022=0.042

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.4305-0.042=0.388\\\\UL=p+z \cdot \sigma_p = 0.4305+0.042=0.473

The 95% confidence interval for the population proportion of female workers in US is (0.388, 0.473).

c) This confidence interval tells us that, with 95% confidence, the true proportion of females in the U.S. labor force is within 0.388 and 0.473.

d) We can conclude that females do not make up a majority of the US labor force, because we can claim, with 95% confidence, that the true proportion of female workers is under 0.473, which is below the 50%.

If the confidence interval have included the value 0.5, we could not be sure (with 95% confidence) that female workers do not represent de majority, as there would be possibility that the true proportion is 0.5.

3 0
4 years ago
Find the value of x. <br><br> not multiple choice
olganol [36]

   

x is the middle line because it divides each catheter into two equal parts.

==> x is half the hypotenuse.

\displaystyle\bf\\x=\frac{30}{2}\\ \\\boxed{\bf x=15}



4 0
3 years ago
GUYS PLEASEE Im begging you I really need help!
yanalaym [24]
I think the answer is d
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3 years ago
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