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tino4ka555 [31]
3 years ago
8

Write in standard form: Four million, three hundred sixty-five thousand, two hundred five A. 4,365,250 B. 4,365,205 C. 4,365,205

,000 D. 4,000,365,205
Mathematics
2 answers:
hichkok12 [17]3 years ago
6 0
The answer is B.

When trying to solve this you first look at how many numbers should it be. If it starts at 4 million then you know its 7 numbers, so any that are longer than that can be dropped. Compare the remaining options and see what is different then read out the whole question.
Anna11 [10]3 years ago
4 0
The answer would be B. 4,365,205. Hope I helped!
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D=rt for r<br> solve for the specified variable
Harlamova29_29 [7]

Answer:

r=d/t

Step-by-step explanation:

d=rt

we are to make r the subject of the formula, so we remove t from the rhs.

we do this by dividing both sides by t

d divided by t= d/t and rt divided by t = r

therefore d/t =rt/t

= r=d/t

4 0
2 years ago
The set of integers is not closed for
Brilliant_brown [7]
Hello,

N is closed for an opération(µ)  means that
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4 0
3 years ago
Hii please help i’ll give brainliest!!
castortr0y [4]
I am going to guess C but I’m not entirely sure
3 0
3 years ago
Read 2 more answers
What is 2/3 divided by 4/5
artcher [175]

Answer:

5/6

Step-by-step explanation:

\frac{2}{3} divided by 4/5  can be written as 2/3 times 5/4

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4 0
3 years ago
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I NEED HELP PLEASE!
olchik [2.2K]

The given sequence is x-1, -2x+2, 4x-4, -8x+8 .

Notice that this is a geometric sequence because here we have equal common ratio.

So, common ratio : r = \frac{a_{2}}{a_{1}}

= \frac{-2x+1}{x-1}

= \frac{-2(x-1)}{(x-1)}Take out -2 as common factor

= -2 Cancel out x - 1.

The formula for general term of a geometric sequence is,

a_{n} =a_{1} r^{n-1}

Where, first term: a_{1} =x-1

We need to find the 10th term of this sequence. So, n = 10.

Next step is to plug in these values in the above formula to get the 10th term. Hence,

a_{10} = (x -1)(-2)^{10-1}

So, A is the correct choice.

8 0
3 years ago
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