Compute the necessary values/derivatives of 
at 
:
Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) at by
###
Another way of doing this would be to solve for the coefficients 
in
by expanding the right hand side and matching up terms with the same power of 
.
Answer
4
Explanation
(1,19) (-2,7)
7-19=-12
-2-1=-3
The divide -12 and -3 and you get 4
Hope this helps
Answer:
No Solutions
Step-by-step explanation:
Multiply the first equation by 5,and multiply the second equation by 2 to get a least common multiple for the x's.
5(4x+6y=3)
2(−10x−15y=−4)
It becomes:
20x+30y=15
−20x−30y=−8
Add these equations to eliminate y:
0=7
Answer:
No solutions.
Answer:
FINE ITS A AND B
Step-by-step explanation:
