You are given two points that could be plotted on a graph (1,-5) and (4,1). The formula for slope is y2-y1/x2 -x1
When plotted into the points it would look like 1-(-5)/4-1= 6/3
6/3=2. So, the slope for these two points is 2.
Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
To get y by itself subtract 2x from both sides. The left side becomes 3y=12-2x. Then divide by 3 on both sides to get y by itself. Which you get y=4-(2/3)x
Team A scored a total of 80,597 points I believe
161,161 + 33 = 161,194
161,194 ÷2 = 80,597
80,597- 33 = 80,564
80,564 + 80,597 = 161,161
28% interest would be your answer, you just divide 560/2000=.28
