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Alisiya [41]
2 years ago
13

A sweater Nala wants to purchase is $24.95 and there is a sale for 15% off. Nala is in a location that does not tax clothing. Ho

w much will she save on the Sweater?
Mathematics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

$2.35 he will save on it.

Step-by-step explanation:

Krishnan Iyer VS Jethalal Gada

<em>y</em><em>o </em>

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If the product of some number and 4 is increased by 121​, the result is 7 times the number. find the number.
arlik [135]
It will be 40.3 approximately
6 0
3 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
Which of the following are solutions to the equation below 4x^2+20x+25=49
KATRIN_1 [288]
( 2x +5)^2 =4

2x+5=2

2x=-3

X=-3/2
4 0
3 years ago
Read 2 more answers
Moira placed $2 in an empty piggy bank, and then added $3 every month. The same day, Nathan placed $5 in an empty piggy bank, an
iren2701 [21]

Answer:

A because they can never be equal because each month Moira adds 5 dollars and Nathan adds 8 dollars

3 0
3 years ago
Read 2 more answers
Is Jeff correct or incorrect?
bulgar [2K]
Jeff is correct because:

2 sides of a triangle must always be longer than the other side, so:

12+8>19
19+8>12
12+19>8

Since all of them are true, Jeff is correct
4 0
3 years ago
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