Which equation represents a line that passes through the two points in the

For this case we have an equation with a variable of the form $y = h (x)$ . Where $h (x) = 3x-19$ . Given the value of $h (x) = 71$ , we want to find the value of the variable "x". So, we have:

$h (x) = 3x-19\\71 = 3x-19$

We must clear "x", for this, we add "19" to both sides of the equation:

$71 + 19 = 3x-19 + 19\\90 = 3x$

We divide between "3" on both sides of the equation:

$\frac {90} {3} = \frac {3x} {3}\\30 = x$

Thus, the value of the variable "x" is 30.

Answer:

$x = 30$

Option A

6 0

3 years ago

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Pleeeeeeessssssseeee help

lozanna [386]

Answer:

0.25, 5/8, 11/16

Step-by-step explanation:

1st, make all of them to decimal or fraction (recommended). I will do decimal this time because it's easier. 11/16 = 0.6875; 5/8 = 0.625 . So we can easily get which one is bigger or smaller.

5 0

3 years ago

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The proprietor of a boutique in New York wanted to determine the average age of his customers. A random sample of 25 customers r

jolli1 [7]

Answer:

$28-2.064\frac{10}{\sqrt{25}}=23.872$

$28+2.064\frac{10}{\sqrt{25}}=32.128$

So on this case the 95% confidence interval would be given by (23.9;32.1)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=28$ represent the sample mean

$\mu$ population mean (variable of interest)

s=10 represent the sample standard deviation

n=25 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=25-1=24$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that $t_{\alpha/2}=2.064$

Now we have everything in order to replace into formula (1):

$28-2.064\frac{10}{\sqrt{25}}=23.872$

$28+2.064\frac{10}{\sqrt{25}}=32.128$

So on this case the 95% confidence interval would be given by (23.9;32.1)

7 0

3 years ago