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Eva8 [605]
3 years ago
9

Which equation represents a line that passes through the two points in the

Mathematics
1 answer:
Andreyy893 years ago
7 0

Answer:

Y-1=5/3(x-3) (aka b)

Step-by-step explanation:

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Write down two expressions for the perimeter of this shape one with brackets and one without
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HELP ME PLS<br> Write the ratio<br> 3/8 with a numerator of 9.
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24

Step-by-step explanation:

3    9

8    

9 times 8

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9x8÷3=24

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In a recent year, grade 8 Washington State public school students taking a mathematics assessment test had a mean score of 281 w
sweet-ann [11.9K]

Answer:

The probability that the mean test score is greater than 290

P(X⁻ > 290 ) = 0.0217

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Mean of the Population (μ) = 281

Standard deviation of the Population = 34.4

Let 'X' be a random variable in Normal distribution

Given X = 290

Z = \frac{x -mean}{\frac{S.D}{\sqrt{n} } } = \frac{290-281}{4.44} = 2.027

<u><em>Step(ii):-</em></u>

<em> The probability that the mean test score is greater than 290</em>

P(X⁻ > 290 ) = P( Z > 2.027)

                    = 0.5 - A ( 2.027)

                   = 0.5 - 0.4783

                   = 0.0217

The probability that the mean test score is greater than 290

P(X⁻ > 290 ) = 0.0217

6 0
3 years ago
A boutique handmade umbrella factory currently sells 37500 umbrellas per year at a cost of 7 dollars each. In the previous year
slega [8]

Answer:

$302,500

Step-by-step explanation:

If cost (C) = $7, then Sales (S) = 37,500 units

If cost (C) = $15, then Sales (S) = 17,500 units

The slope of the linear relationship between units sold and cost is:

m=\frac{37,500-17,500}{7-15}\\m= -2,500

The linear equation that describes this relationship is:

s-s_0 =m(c-c_0)\\s-17500 =-2500(c-15)\\s(c)=-2500c + 55,000

The revenue function is given by:

R(c) = c*s(c)\\R(c)=-2500c^2 + 55,000c

The cost at which the derivative of the revenue equals zero is the cost that yields the maximum revenue.

\frac{d(R(c))}{dc}=0 =-5000c + 55,000\\c=\$11

The optimal cost is $11, therefore, the maximum revenue is:

R(11)=-2500*11^2 + 55,000*11\\R(11)=\$ 302,500

4 0
3 years ago
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