<h3>
Answer: Choice D) </h3>
Work Shown:
![(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\](https://tex.z-dn.net/?f=%28f%2Bg%29%28x%29%20%3D%20f%28x%29%2Bg%28x%29%5C%5C%5C%5C%28f%2Bg%29%28x%29%20%3D%20%5Cfrac%7Bx-23%7D%7Bx%5E2%2B9x-36%7D%2B%5Cfrac%7B1%7D%7Bx%2B12%7D%5C%5C%5C%5C%28f%2Bg%29%28x%29%20%3D%20%5Cfrac%7Bx-23%7D%7B%28x%2B12%29%28x-3%29%7D%2B%5Cfrac%7B1%28x-3%29%7D%7B%28x%2B12%29%28x-3%29%7D%5C%5C%5C%5C%28f%2Bg%29%28x%29%20%3D%20%5Cfrac%7Bx-23%2B1%28x-3%29%7D%7B%28x%2B12%29%28x-3%29%7D%5C%5C%5C%5C%28f%2Bg%29%28x%29%20%3D%20%5Cfrac%7Bx-23%2Bx-3%7D%7Bx%5E2%2B9x-36%7D%5C%5C%5C%5C%28f%2Bg%29%28x%29%20%3D%20%5Cfrac%7B2x-26%7D%7Bx%5E2%2B9x-36%7D%5C%5C%5C%5C)
We must require that
and
to avoid having 0 in the denominator. This is why choice D is the answer.
Answer:
-1.5,-1,0,0.5,1 is the answer
Answer:
15, 30, 60, 120, 240, <u>480</u>.
Step-by-step explanation:
You multiply the numbers by 2 to get to the next number.
For example, 15*2 is 30. 30*2 is 60. 60*2 is 120, etc..
Answer:
hello there
your answer is <u>1</u>
Step-by-step explanation:
hope it helps....
thanks for the free points!!!