Area of circle= pi times radius^2
diameter=2 times radius
radius=diameter/2
diameter=12
radius=12/2
radius=6
pi times r&+^2
pi times 6^2
pi times 36
aprox pi=3.14
113.04 in^2
Cost =16000
rate of depreciation = 35%
written down value = 2000
depreciation for one year =16000*35% = 5600
5600*2 = 11200+5600*6\12 = 2000
the car is 2.5 years old. It has been depreciated for 2 whole years and half
years.
Answer:
The answer would be 7mn^5 - 2m^6 + 14m^2n^4 - 5m^3n^3 + n^6
Step-by-step explanation:
In order to find that answer, start by grouping all of the terms by their variable values. Ones that are the same should be combined.
8mn^5 - mn^5 = 7mn^5
2m^6 - 4m^6 = -2m^6
5m^2n^4 + 9m^2n^4 = 14m^2n^4
-m^3n^3 - 4m^3n^3 = -5m^3n^3
n^6 = n^6
Now we simply combine them all to get
7mn^5 - 2m^6 + 14m^2n^4 - 5m^3n^3 + n^6
Answer:
7
O
⋅
(
24
h
O
)
⋅
(
25
O
)
⋅
31
.
X
⋅
7
=
7
X
24
=
7
X
7
O
⋅
(
24
h
O
)
⋅
(
25
O
)
⋅
31
=
130200
O
3
h
Answer:
The actual building will be 7.5 m tall
Step-by-step explanation:
Given the scale model value of the building, we want to find the actual height of the building
From the scale model;
1 cm = 0.5m
Thus 15 cm will be 15 * 0.5 = 7.5 m
