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3 years ago

1106.666667 to the nearest whole number

Mathematics

2 answers:

saveliy_v [14]3 years ago

8 0

Answer:

1106.666667 rounds to 1107

Step-by-step explanation:

We look at the whole number, 6

Then look at the tenths place .6

Since 6 is greater than or equal to 5, we round the whole number up one place to 7

1106.666667 rounds to 1107

Anna007 [38]3 years ago

4 0

Answer:

1106.666667 to the nearest whole number

1107

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Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

Can someone please help me please I really need help please help

mr Goodwill [35]

Answer:

K'(4, -4)
L'(8, -4)
M'(8, 8)
N'(4, 8)

Step-by-step explanation:

Dilation centered at the origin multiplies every coordinate value by the scale factor.

K(1, -1) ⇒ K' = 4(1, -1) = (4, -4)

L(2, -1) ⇒ L' = 4(2, -1) = (8, -4)

M(2, 2) ⇒ M' = 4(2, 2) = (8, 8)

N(1, 2) ⇒ N' = 4(1, 2) = (4, 8)

6 0

3 years ago