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3 years ago

1106.666667 to the nearest whole number

Mathematics

2 answers:

saveliy_v [14]3 years ago

8 0

Answer:

1106.666667 rounds to 1107

Step-by-step explanation:

We look at the whole number, 6

Then look at the tenths place .6

Since 6 is greater than or equal to 5, we round the whole number up one place to 7

1106.666667 rounds to 1107

Anna007 [38]3 years ago

4 0

Answer:

1106.666667 to the nearest whole number

1107

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Daniel dives into a swimming pool. The height of his head is represented by the function h(t) = -8t2 - 28t + 60, where t is the

8_murik_8 [283]

So, h(t) is how far is Daniel's head from the surface of the water, namely the surface itself is when the height is nill, so his head is at the surface and the height of it is just 0, thus h(t) = 0. Namely, what is "t" when h(t) is 0?

$\bf h(t)=-8t^2-28t+60\implies \stackrel{h(t)}{0}=-8t^2-28t+60
\\\\\\
0=-2t^2-7t+15\implies 2t^2+7t-15=0\implies (2t+3)(t-5)=0
\\\\\\
\begin{cases}
2t+3=0\implies 2t=-3\implies &t=-\frac{3}{2}\\\\
t-5=0\implies &\boxed{t=5}
\end{cases}$

clearly the seconds cannot be a negative unit, so is not -3/2.

6 0

3 years ago

What is the function written in vertex form?

lys-0071 [83]

Answer:

The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If the coefficient a is positive then the parabola open up and the vertex is a minimum

If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

$f(x)=3(x+4)^{2}-6$

The vertex is the point (-4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case B) we have

$f(x)=3(x+4)^{2}-38$

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

$f(x)=3(x-4)^{2}-6$

The vertex is the point (4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case D) we have

$f(x)=3(x-4)^{2}-38$

The vertex is the point (4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

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3 years ago

3.) Find the domain and range for each of the following functions.

Delvig [45]

Domain is x’s and range is y’s.

For a, the domain is -2<=x<1
For a, the range is 1<=y<2

For b, the domain is 1<=x<=2
For b, the range is -2<=y<=2

(The <= is the ones with a line under, meaning equal to, if that makes sense. So write with a line under rather than equal sign)
Hope this helps!

6 0

3 years ago

What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the

marishachu [46]

The sum of all the measurements is just the average times the number.

$\bar x = \frac{1}{n} \sum_{i=1}^n x_i$

$\sum_{i=1}^n x_i = n \bar x$

So if the average of all 92 is 7 the sum of those is $92 \times 7$

The average of the last two is 7.2 so their sum is $2 \times 7.2$

That means the sum of the first 90 is $92 \times 7 - 2 \times 7.2$

so the average of the first 90 is

$\dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556$ cm

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3 years ago

Simplify 8 2(10 – r). a. 7r – 18 b. –2r – 18 c. –2r – 9 d. 28 – 2r

fiasKO [112]

8 + 2(10 - r) = 8 + 20 - 2r = 28 - 2r

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3 years ago