Question

2,11,20 find the t15

Answer 1

Answer:

128

Step-by-step explanation:

There is a common difference between consecutive terms, that is

11 - 2 = 20 - 11 = 9

This indicates the sequence is arithmetic with n th term

$t_{n}$ = t₁ + (n - 1)d

where t₁ is the first term and d the common difference

Here t₁ = 2 and d = 9 , thus

t₁₅ = 2 + (14 × 9) = 2 + 126 = 128