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2 years ago

Solve/Find the value of a

Mathematics

2 answers:

Anettt [7]2 years ago

6 0

Answer:

a= -19 :)

Step-by-step explanation:

thats it lol

bogdanovich [222]2 years ago

4 0

Answer:

a= -19

Step-by-step explanation:

I worked it out too

You might be interested in

The equation cos−1 = x can be used to determine the measure of angle BAC.

Sergio [31]

we know that

in the right triangle ABC

the value of cosine of angle x is equal to

$cos(x)=\frac{AC}{AB}$

we have

$AC=3.4\ cm\\AB=10\ cm$

substitute the values

$cos(x)=\frac{3.4}{10}=0.34$

Find the measure of angle x

$x=cos(x)^{-1} =arc\ cos(0.34)=70.12\°$

Round to the nearest whole degree

$x=70\°$

therefore

<u>the answer is</u>

$70\°$

5 0

2 years ago

Read 2 more answers

mojhsa [17]

Answer:

84°

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary:

∠A = 180° -96°

∠A = 84°

5 0

3 years ago

What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

PIT_PIT [208]

9514 1404 393

Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

3 0

2 years ago

When 2(3/5 x + 2/3 y - 1/4 x -1 1/2 y + 3 )is simplified, what is the resulting expression?

vovangra [49]

Answer:

Simplifying the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$ we get $\mathbf{42x-100y-360}$

Step-by-step explanation:

We need to simplify the expression: $2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$

First we will solve terms inside the bracket

$2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)$

Converting mixed fraction $1\frac{1}{2} y$ into improper fraction, we get: $\frac{3}{2}y$

Replacing the term:

$2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)$

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

$2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)$