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GREYUIT [131]
1 year ago
10

Given that f(x) = 2x+4 and h(x) = x³, find (h o f)(1). (hof)(1)= (Simplify your answer.)

Mathematics
1 answer:
Murrr4er [49]1 year ago
8 0

Answer:

216

Step-by-step explanation:

Plug in 1 to f(x). 2(1) + 4 = 6

Plug that answer in to h(x).

6^3 = 6*6*6 = 216

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CAN SOMEONE HELP ME WITH WIYH THIS ?????
fomenos

Answer:

x = 14

Angle B = 121°

Angle C is 59°

Step-by-step explanation:

First we'll find x, then we'll find Angle B (by substituting in x), then we'll find Angle C (bc Angle B and C are supplementary--that us, they add up to 180°)

10x-19 = 7x+23 subtract 7x

3x-19 = 23 add 19

3x = 42 divide by 3

x = 14

Angle B is 10x-19, and if x=14, then its 10(14)-19

Angle B is 140-19

which is 121°

Angle B = 121°

Angle B and Angle C add up to 180°

121° + c = 180°

c = 180-121

Angle C is 59°

8 0
2 years ago
Last year, a toy company made $14,476,375 from sales of a stuffed animal pillow.
Anna [14]
14,000,000 is the answer please give me points
7 0
3 years ago
Read 2 more answers
Juan divided 1/2 jar of fish food into 7 equal parts. He feeds his fish one part each day.
amid [387]
1/14 is the correct answer
5 0
2 years ago
Read 2 more answers
Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17
Luden [163]

The larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

ax^2 + bx + c = 0

Then its roots are given as:

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The given quadratic equation is

y = -2.2x^2 + 63.5x - 17

now, the roots of the equation are

x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

#SPJ1

7 0
2 years ago
Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =&#10;\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
</span>Plug this into y = 4^{-x} to find letter c:
y = 4^{-x}\\ &#10;y = 4^{-4}\\ &#10;y =  \frac{1}{4^{4}} \\  &#10;y= \frac{1}{256}
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
5 0
3 years ago
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