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2 years ago

Write an equation to a line that is perpendicular to y= -0.3x +6 that passes through points (3,-8)

Mathematics

1 answer:

Mandarinka [93]2 years ago

5 0

Answer:

.3x-8.9

Step-by-step explanation:

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Please pls pls pls ANSWER ASAP!!! :P :)

klasskru [66]

Answer:

20-15z

Step-by-step explanation:

-1+21-15z

20-15z

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3 years ago

Read 2 more answers

PLZZZ HELP IM IN A RUSH

cupoosta [38]

1/3 - 2/9 - 1/3

= -2/9
(Decimal: -0.222222)

4 0

2 years ago

Vanessa deposited money into a bank account that earned 1.25% simple interest each year. After 12 year, she had earned $5.00 in

svetlana [45]

Answer: 800$ is the answer.

multiply to by both sides, remove 1/2.

Have a blessed day.

6 0

2 years ago

A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w

vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance = Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance = Do + Vo*t + 0.5*a*t^2

(1 foot)= (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D = Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0 (Ground)

We substitute in the equation, and solve for t (time)

(0) = (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s < 2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0

3 years ago

The heights of a maple tree and a cherry tree have a ratio of 5:2. If the maple tree grew 20 cm and 20 cm was cut off the top of

elena-14-01-66 [18.8K]

Let x be the heights of a maple tree and y be the height of the cherry tree.
We know:
 $\frac{x}{y} = \frac{5}{2}$
The new ratio is obtained like this:
 $\frac{x+20}{y-20} = \frac{3}{1}$ .
From the above equation we get $x= (y-20)\frac{3}{1} -20$ .
then $\frac{ (y-20)\frac{3}{1} -20}{y} = \frac{5}{2}$
Solving the above equation for y we get: $y=160$
So $x=400$
So the first tree is (400-160=240) more taller than cherry tree.

7 0

2 years ago