Y = x⁵ sin(2x ) cos(4x)
y' = d/dx (x⁵ sin (2x) × cos (4x) + x⁵ sin(2x) ). ×
d/dx (cos(4x) )
y' = 5x⁴ sin(2x) cos(4x)+2x⁵ cos(2x) cos(4x) -4x⁵ sin(2x) sin(4x)
Answer:
here down is the answer
(2y/5y)^3+4y^2+6y
8y^3/125y^3 +16y^2+6y
8/125+16y^2+6y
8/125+16y^2+6y=0
16y^2+6y+8/125=0
it is in the form of quadratic equation
formula :
x=(-b+-square root of b^2-4ac) /2a
here a=16,b=6&c=8/125
x=(-b+-square root of b^2-4ac)/2a
x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation
x=(-6+-31.91)/2
so
x=(-6+31.91)/2 first (+);
x=25.91/2
x=12.955;
x=(-6-31.91)/2 then(-);
x=-37.91/2
x=-18.955 ;
ans is = 12.955&-18.955;
Answer:
$90.00
Step-by-step explanation:
Given
--- base fee
--- rate
--- individuals
Required
Determine the total amount paid (y)
The relationship between the variables is:
This gives:
<em>Hence, the amount is $90.00</em>
1/3(1/2)8(6)(10)=80
Your welcome
The given expression, 81a^6 - 100, is a difference of two squares. The first term 81a^6 is a square of 9a³. The second term, 100, is a square of 10. The factors of the given expression is therefore, (9a³ - 10) x (9a³ + 10).
