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3 years ago

Would this be sin, cos, or tan?

Mathematics

2 answers:

MAXImum [283]3 years ago

7 0

Answer: cos

Step-by-step explanation:

You don't have a value for the side opposite the angle, you only have your hypotenuse and your adjacent side. Hope this helps.

sesenic [268]3 years ago

5 0

Answer:

cos

Step-by-step explanation:

its adjacent over hypotenuse

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Answer:

see below

Step-by-step explanation:

The formula for the amount resulting from P earning interest at rate r continuously compounded is ...

A = Pe^(rt)

for P=2500 and r=0.12, this becomes ...

A = 2500e^(0.12t)

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3 years ago

Using an applet, we found that the theory-based test results in a t-statistic of -7.25 and p-value less than 0.0001. State your

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Answer:

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Step-by-step explanation:

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3 years ago

Which of the following represents a function?

Molodets [167]

What are the functions?

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3 years ago

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Ket [755]

Answer:

Step-by-step explanation:

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3 years ago

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The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

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3 years ago