One of the factors of x³ - 27 is x - 3. What is the other factor?

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

6 0

Answer:

We know that, a³ - b³ = (a - b)(a² + ab + b²)

Now,

x³ - 27
(x)³ - (3)³
(x - 3)(x² + 3x + 9)

Therefore,

<u>(x² + 3x + 9)</u> is the other factor.

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Alexxx [7]

Answer:

Power property for both

Step-by-step explanation:

The power property of logarithms says that if there is an exponent in a logarithm, then that exponent can be pulled to the front.

In the first question, 5 is at the front of the logarithm because it has been pulled from 3. If you move the 5 back to the 3, it would be 3^5, which is 243.

In the second question, 2 is at the front of the logarithm as it has been pulled from the 9. If you move the 2 back to the 9, it would be 9^2, or 81.

Example:

log10^2 would be equal to 2log10.

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3 years ago

The point (5, −2) is on the terminal ray of angle θ, which is in standard position. Without evaluating, explain how you would fi

Anni [7]

1. Check the picture attached.

let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)

ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.

2. m(PNM)=∅ as can be easily checked

In triangle PNM, NP=5, PM=2 and NM= $\sqrt{ 5^{2} + 2^{2} }= \sqrt{25+4}= \sqrt{29}$ units

3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse

sin ∅ = opp/hyp= $\frac{2}{\sqrt{29}}$

cos ∅ = adj/hyp= $\frac{5}{\sqrt{29}}$

tan ∅ = opp/adj=2/5

cot ∅ = adj/opp=5/2

sec ∅ = hyp/adj= $\frac{\sqrt{29}}{5}$

csc ∅ = hyp/opp= $\frac{\sqrt{29}}{2}$