How many games did he win? Help

Need help with all three

Pachacha [2.7K]

Answer:

i can only do 2 and 3 sorry

2. a

3.d

Step-by-step explanation:

7 0

3 years ago

HELP PLEASE. For parallelogram LMNO, if m∠L = 3x - 25 and m∠N = 2x - 10, find m∠M.

Dvinal [7]

In a parallelogram opposite angles are congruent, that means:

Angle L = Angle N, replace L & N by they respective value, then

3x-25 = 2x-10 ==> x=15 , Now plug the value of x in any of the 2 sides
3(15) -25 =20°

hence Angle L =- Angle N = 20°

Now let's calculate Angle M. In a parallelogram the adjacent angle are supplementary, that means their sum = 180°, then

Angle N + Angle N = 180°==> Angle M = 180°-20° = 160°

5 0

3 years ago

6 for $14.34<br> each. Please I really need help with this.

Marrrta [24]

6 items for $14.34 each is $86.04.

3 0

2 years ago

Please help me <br>ineed it now

yanalaym [24]

Answer:

look at explanation

Step-by-step explanation:

To solve all of these questions you just need to scale. While scaling you can divide or multiply.

1. $\frac{180 km}{4 hrs}$ (divide by 4 to get unit rate)

unit rate = $\frac{45km}{1hr}$

2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know $\frac{40 miles}{1 hr}$ , the answer is...

"It'll only take one hour to travel 40 miles. This is correct because the unit rate is $\frac{40 miles}{1 hr}$ . "

3. Knowing that the constant speed of the plane is $\frac{800 km}{1 hour\\}$ , we can scale then add half of the unit rate to get our answer.

$\frac{800 km}{1 hour\\}$ x 3 = $\frac{2400 km}{3 hrs}$ 800 x 3 = 2400

then add half of unit rate which is $\frac{400 km}{30 mins}$ $\sqrt[2]{800}$ = 400

so, our answer is $\frac{2800 km}{3.5 hours}$

4. $\frac{3km}{30 mins}$ <--- ( divided by 2) $\frac{6 km}{1 hr}$ ( multiplied x 2.5) ---> $\frac{15 km}{2.5 hrs}$

To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.

Elmer would take 2 and a half hours to ride 15 km.

5. The boys speed is $\frac{4 km}{1 hr}$ . All we need to do is divide by 2. $\sqrt[2]{8}$ = 4

3 0

3 years ago

A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline

dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So $P(B) = 0.35$

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

$P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125$

Probability

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667$

46.67% probability that they flew with airline B.

5 0

3 years ago