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Zepler [3.9K]
3 years ago
10

Find the value of 2^-3*3^-2

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

2^{-3}\cdot 3^{-2}

2^-3=\frac{1}{2^3}

3^-2=\frac{1}{3^2}

\frac{1}{2^3}*\frac{1}{3^2}

\frac{1*1}{2^3*3^2}

2^3*3^2=72

=\frac{1}{72}

Hope this helps!

Thanks!

-Charlie


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