Answer:
60 weeks
Step-by-step explanation:
Factor both numbers 12 and 15:
Find LCM(12,15). The common factor is only 3, multiply ths common factor by all factors that remain. Then

This means that the fewest number of weeks that will pass before both machines are cleaned again in the same week is 60 weeks.
Answer: Section B
Step-by-step explanation: A rhombus is a parallelogram.
With what? I don't see a question
Answer:
z+15
Step-by-step explanation:
Cross multiply and divide. 70z = 42*25
Hope this helps!!
52 and 48 if you take away 2 from 50 then,add it to the other 50 52+48