Question

What is the oblique asymptote of gx) = x2-3x-5?

Answer 1

Answer:

B) $y=x-5$

Step-by-step explanation:

Because $g(x)=\frac{x^2-3x-5}{x+2}$ simplifies to $x-5+\frac{5}{x+2}$, we only care about the quotient, which will be our oblique asymptote equation. Therefore, the oblique asymptote for the function will be $y=x-5$. See the attached graph for a visual.