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Oxana [17]
3 years ago
12

What is the oblique asymptote of gx) = x2-3x-5?

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

B) y=x-5

Step-by-step explanation:

Because g(x)=\frac{x^2-3x-5}{x+2} simplifies to x-5+\frac{5}{x+2}, we only care about the quotient, which will be our oblique asymptote equation. Therefore, the oblique asymptote for the function will be y=x-5. See the attached graph for a visual.

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a payday loan store charges $40 for one month loan of $300. what annual interest rate is This equivalent to
madreJ [45]
Annual would be $480!
3 0
3 years ago
Which statement about the graph is true? On a coordinate plane, a line goes through points (0, 2), (2, 3), (4, 4), (6, 5). The g
Tema [17]

The answer is C. The graph does not show a proportional relationship because each point written as a ratio gives a different value.

Hope this helped! If it didn't please tell me what went wrong so I can fix it.

6 0
3 years ago
Read 2 more answers
On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu
CaHeK987 [17]

Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

  • n=5
  • 2n=10
  • m=4

P=\frac{10!}{4!*(10-4)!}*0.5^{10}

P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205

8 0
3 years ago
In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C', A', and B'
sp2606 [1]

Answer:

The correct answer is <u>B. 15 units</u>

Step-by-step explanation:

6 0
2 years ago
One number is 2 less than a second number. Twice the second number is 5 less than 3 times the first. Find the two numbers.
Evgen [1.6K]

Answer:

9 and 11  

Step-by-step explanation:

First number = x -2

Second number = x

  and   2x = 3(x-2)  - 5

            2x = 3x - 6 - 5

             x = 11

              first number = 11-2 = 9

8 0
2 years ago
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