3 years ago

What is the oblique asymptote of gx) = x2-3x-5?

Mathematics

1 answer:

oee [108]3 years ago

3 0

Answer:

B) $y=x-5$

Step-by-step explanation:

Because $g(x)=\frac{x^2-3x-5}{x+2}$ simplifies to $x-5+\frac{5}{x+2}$ , we only care about the quotient, which will be our oblique asymptote equation. Therefore, the oblique asymptote for the function will be $y=x-5$ . See the attached graph for a visual.

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