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Oxana [17]
3 years ago
12

What is the oblique asymptote of gx) = x2-3x-5?

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

B) y=x-5

Step-by-step explanation:

Because g(x)=\frac{x^2-3x-5}{x+2} simplifies to x-5+\frac{5}{x+2}, we only care about the quotient, which will be our oblique asymptote equation. Therefore, the oblique asymptote for the function will be y=x-5. See the attached graph for a visual.

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What are the coordinates of the point on the directed line segment from (-6, -3) to
melamori03 [73]

Given:

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.

To find:

The coordinates of that point.

Solution:

Section formula: If point divides a line segment in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

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Point=\left(\dfrac{6(5)+5(-6)}{6+5},\dfrac{6(8)+5(-3)}{6+5}\right)

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Therefore, the coordinates of the required point are (0,3).

3 0
3 years ago
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gulaghasi [49]

Answer:

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