Hello
the equation is y = ax+b
a the slop a = 4
y = 4x+b
the line <span>passes through (3, -10) : -10 = 6(3)+b
b = -28
</span>the equation is y = 6x-28
If the data set represents the number of rings each person is wearing, being: 0,2,4,0,2,3,2,8,6, the interquartile range of the data is 2. Being, 4 as the Q1, 3 as the Q2 or median, and 6 as the Q3. Where the formula of getting the interquartile range is IQR= Q1-Q2.
Answer:
144
Step-by-step explanation:
quadratic formula:
x = <u>-b ± √(b² - 4ac)</u>
2a
7x² - x = 7
subtract 7 from both sides:
7x² - x - 7 = 0
plug values into the quadratic formula:
x = <u>-(-1) ± √((-1)²- 4(7)(-7))</u>
2(7)
simplify:
x = <u>1 ± √(197)</u>
14
Answer:
≈ 1/2 teaspoon
4 2/5 * .11 = .484 teaspoon
Hope this helps :)
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