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Alenkasestr [34]

3 years ago

15

True or false: When moving to a bigger unit we divide or move our decimal to the left.

1 answer:

Lerok [7]3 years ago

5 0

False because, If you have to move the decimal point to the right to get the original number, the exponent will be a positive number, if you have to move the decimal point to the left to get the original number, the exponent will be a negative number.

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5(8x-3)+4(-6x-4)<br> Distribute then simplify

Nikitich [7]

Answer:

16x - 31

Step-by-step explanation:

Write the full equation:

5(8x - 3) +4(-6x - 4)

Distribute:

40x - 15 - 24x - 16

Combine Like Terms:

16x - 15 - 16

Your answer is:

16x - 31

5 0

3 years ago

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Jillian needs to buy a new laptop for the school year. The list price for the laptop is $479.99. Is it a better

Galina-37 [17]

Answer:

$100 rebate

Step-by-step explanation:

$479.99-$100.00= $379.99 or $479.99-20% =$383.99 so the $100.00 rebate a better offer

4 0

4 years ago

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Kevin counts 75 chicks in the hen house. He also sees more chicks outside the hen house. How can Kevin count to find how many ch

stellarik [79]

What we know:

we know that there are <u>75</u> chicks in the hen house, we also know that in all there are 108 chicks

What we need to find:

we need to find out how many chicks were outside

Answer equation:

108 - 75 = 33

8 0

3 years ago

Use factoring to solve the quadratic equation x2 − 2x − 3 = 12.

melomori [17]

Answer:

$x_1=5\\x_2=-3$

Step-by-step explanation:

You have the following quadratic equation given in the problem:

$x^{2}-2x-3=12$

You must make the equation equal to zero, as following:

$x^{2}-2x-3-12=0$

Add like terms:

$x^{2}-2x-15=0$

Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:

$(x-5)(x+3)=0\\x_1=5\\x_2=-3$

7 0

3 years ago

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Which of the following is true about the expression sqrt3*sqrt2

Mars2501 [29]

Answer:

<h2>Option B is the right answer.</h2>

Step-by-step explanation:

$\sqrt{3} , \sqrt{2}$ are two irrational numbers, that is, they can not be shown as the fraction of two integers.

$\sqrt{3} \times\sqrt{2} = \sqrt{6}$

$\sqrt{6}$ is also a irrational number, since it also can not be represented as the fraction of integers.

Hence, the given expression represent the product of two irrational number and is equivalent to an irrational number.

3 0

3 years ago

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